Morphocompletion for #5235 ⟨a, b | aabbaba=bbaa

Solved by morph:2/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbaba ⇒ bbaa
2. aabbabbbaa ⇒ bbabbaa
3. aabbabbbbbaa ⇒ bbabbbbaa
4. aabbabbbabbaa ⇒ bbabbabbaa
5. aabbabbbbbbbaa ⇒ bbabbbbbbaa
6. aabbabbbabbbbaa ⇒ bbabbabbbbaa
7. aabbabbbbbabbaa ⇒ bbabbbbabbaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] aa, [2/2] ba, [2/3] ab
Length 3:[3/0] bbb, [3/1] bba, [3/2] abb, [3/3] aab, [3/4] baa, [3/5] bab, [3/6] aba
Length 4:[4/0] aabb, [4/1] bbaa, [4/2] bbab, [4/3] bbbb, [4/4] babb, [4/5] abba, [4/6] bbba
Length 5:[5/0] aabba, [5/1] bbabb, [5/2] bbbaa, [5/3] babbb, [5/4] abbab, [5/5] bbbbb, [5/6] bbbba
Length 6:[6/0] aabbab, [6/1] bbabbb, [6/2] bbbbaa, [6/3] abbabb, [6/4] babbbb, [6/5] babbaa, [6/6] bbbbba
Length 7:[7/0] aabbabb, [7/1] abbabbb, [7/2] bbabbbb, [7/3] bbbbbaa, [7/4] bbabbaa, [7/5] babbbbb, [7/6] bbabbba

Considering [length 2 / frequency 2] ba=c.

Step 2

Rewriting system is complete. See a, b | aabbaba=bbaa.