| Back: | ⟨a, b | aabbaba=baaa⟩ |
|---|
Solved by morph:2/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabbaba ⇒ baaa |
| 2. | aabbabbaaa ⇒ baabaaa |
| 3. | aabbabbabaaa ⇒ baababaaa |
| 4. | aabbabbaabaaa ⇒ baabaabaaa |
| 5. | aabbabbababaaa ⇒ baabababaaa |
| 6. | aabbabbaababaaa ⇒ baabaababaaa |
| 7. | aabbabbabaabaaa ⇒ baababaabaaa |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb |
|---|---|
| Length 3: | [3/0] aab, [3/1] bba, [3/2] abb, [3/3] aaa, [3/4] bab, [3/5] aba, [3/6] baa |
| Length 4: | [4/0] aabb, [4/1] abba, [4/2] baaa, [4/3] bbab, [4/4] baba, [4/5] abaa, [4/6] babb |
| Length 5: | [5/0] aabba, [5/1] abaaa, [5/2] abbab, [5/3] babba, [5/4] bbabb, [5/5] bbaba, [5/6] babaa |
| Length 6: | [6/0] aabbab, [6/1] babaaa, [6/2] bbabba, [6/3] abbabb, [6/4] abbaba, [6/5] aabaaa, [6/6] babbaa |
| Length 7: | [7/0] aabbabb, [7/1] abbabba, [7/2] baabaaa, [7/3] ababaaa, [7/4] bbabbaa, [7/5] babbaba, [7/6] bbabbab |
Considering [length 2 / frequency 1] ba=c.
Rewriting system is complete. See ⟨a, b | aabbaba=baaa⟩.