| Back: | ⟨a, b | aabbaba=abab⟩ |
|---|
Solved by morph:4/4. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabbaba ⇒ abab |
| 2. | abababbaba ⇒ ababbab |
| 3. | ababbabbaba ⇒ ababbbab |
| 4. | ababbbabbaba ⇒ ababbbbab |
| 5. | ababbababbaba ⇒ ababbabbab |
| 6. | abababbabbab ⇒ ababbabbbaba |
| 7. | ababbbbabbaba ⇒ ababbbbbab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 35 | lf:28,lp:6,ls:1,rf:22,rp:7,rs:6,lprp:6,lsrp:1,lprs:5 |
|---|---|---|---|
| [2/1] | ba | 33 | lf:27,ls:6,rf:16,rs:1 |
| [2/2] | bb | 15 | lf:15,rf:15 |
| [2/3] | aa | 2 | lf:1,lp:1 |
| [3/0] | aba | 27 | lf:15,lp:6,ls:6,rf:8,rp:7,rs:1,lprp:6,lsrp:6,lprs:1 |
| [3/1] | bab | 22 | lf:21,ls:1,rf:15,rs:6 |
| [3/2] | abb | 12 | lf:12,rf:8 |
| [3/3] | bba | 12 | lf:12,rf:8 |
| [3/4] | bbb | 3 | lf:3,rf:7,a:2 |
| [3/5] | aab | 2 | lf:1,lp:1 |
| [4/0] | abab | 15 | lf:9,lp:6,rf:7,rp:7,rs:1,re:1,lprp:6 |
| [4/1] | baba | 15 | lf:9,ls:6,rf:1,rs:1 |
| [4/2] | bbab | 13 | lf:12,ls:1,rf:8,rs:5 |
| [4/3] | babb | 11 | lf:11,rf:8,a:1 |
| [4/4] | abba | 10 | lf:10,rf:4 |
| [4/5] | abbb | 2 | lf:2,rf:4,a:2 |
| [4/6] | bbba | 2 | lf:2,rf:4,a:2 |
| [5/0] | bbaba | 13 | lf:7,ls:6,rf:1,rs:1 |
| [5/1] | ababb | 11 | lf:7,lp:4,rf:6,rp:6,lprp:4,a:1 |
| [5/2] | abbab | 11 | lf:10,ls:1,rf:4,rs:2 |
| [5/3] | babba | 9 | lf:9,rf:4,a:1 |
| [5/4] | bbabb | 4 | lf:4,rf:2,a:2 |
| [5/5] | ababa | 4 | lf:2,lp:2,a:1 |
| [5/6] | babab | 3 | lf:3,a:1 |
| [6/0] | abbaba | 13 | lf:7,ls:6 |
| [6/1] | babbab | 10 | lf:9,ls:1,rf:4,rs:2,a:1 |
| [6/2] | ababba | 7 | lf:5,lp:2,rf:3,rp:3,lprp:1,a:1 |
| [6/3] | ababbb | 4 | lf:2,lp:2,rf:3,rp:3,lprp:2,a:2 |
| [6/4] | bbabba | 4 | lf:4,rf:1,a:2 |
| [6/5] | ababab | 4 | lf:2,lp:2,a:1 |
| [6/6] | bababb | 3 | lf:3,a:1 |
| [7/0] | babbaba | 11 | lf:6,ls:5,a:1 |
| [7/1] | ababbab | 7 | lf:5,lp:2,rf:3,rp:3,rs:1,re:1,lprp:1,a:1 |
| [7/2] | bbabbab | 5 | lf:4,ls:1,rf:1,rs:1,a:2 |
| [7/3] | abababb | 4 | lf:2,lp:2,a:1 |
| [7/4] | bababba | 3 | lf:3,a:1 |
| [7/5] | ababbbb | 2 | lf:1,lp:1,rf:2,rp:2,lprp:1,a:6 |
| [7/6] | babbabb | 2 | lf:2,rf:2,a:2 |
Considering [length 4 / frequency 4] abba=c.
Rewriting system is complete. See ⟨a, b | aabbaba=abab⟩.