| Back: | ⟨a, b | aabbaba=abab⟩ |
|---|
Solved by morph:4/4. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabbaba ⇒ abab |
| 2. | abababbaba ⇒ ababbab |
| 3. | ababbabbaba ⇒ ababbbab |
| 4. | ababbbabbaba ⇒ ababbbbab |
| 5. | ababbababbaba ⇒ ababbabbab |
| 6. | abababbabbab ⇒ ababbabbbaba |
| 7. | ababbbbabbaba ⇒ ababbbbbab |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa |
|---|---|
| Length 3: | [3/0] aba, [3/1] bab, [3/2] abb, [3/3] bba, [3/4] bbb, [3/5] aab |
| Length 4: | [4/0] abab, [4/1] baba, [4/2] bbab, [4/3] babb, [4/4] abba, [4/5] abbb, [4/6] bbba |
| Length 5: | [5/0] bbaba, [5/1] ababb, [5/2] abbab, [5/3] babba, [5/4] bbabb, [5/5] ababa, [5/6] babab |
| Length 6: | [6/0] abbaba, [6/1] babbab, [6/2] ababba, [6/3] ababbb, [6/4] bbabba, [6/5] ababab, [6/6] bababb |
| Length 7: | [7/0] babbaba, [7/1] ababbab, [7/2] bbabbab, [7/3] abababb, [7/4] bababba, [7/5] ababbbb, [7/6] babbabb |
Considering [length 4 / frequency 4] abba=c.
Rewriting system is complete. See ⟨a, b | aabbaba=abab⟩.