Morphocompletion for #5228 ⟨a, b | aabbaba=abab

Solved by morph:4/4. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbaba ⇒ abab
2. abababbaba ⇒ ababbab
3. ababbabbaba ⇒ ababbbab
4. ababbbabbaba ⇒ ababbbbab
5. ababbababbaba ⇒ ababbabbab
6. abababbabbab ⇒ ababbabbbaba
7. ababbbbabbaba ⇒ ababbbbbab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa
Length 3:[3/0] aba, [3/1] bab, [3/2] abb, [3/3] bba, [3/4] bbb, [3/5] aab
Length 4:[4/0] abab, [4/1] baba, [4/2] bbab, [4/3] babb, [4/4] abba, [4/5] abbb, [4/6] bbba
Length 5:[5/0] bbaba, [5/1] ababb, [5/2] abbab, [5/3] babba, [5/4] bbabb, [5/5] ababa, [5/6] babab
Length 6:[6/0] abbaba, [6/1] babbab, [6/2] ababba, [6/3] ababbb, [6/4] bbabba, [6/5] ababab, [6/6] bababb
Length 7:[7/0] babbaba, [7/1] ababbab, [7/2] bbabbab, [7/3] abababb, [7/4] bababba, [7/5] ababbbb, [7/6] babbabb

Considering [length 4 / frequency 4] abba=c.

Step 2

Rewriting system is complete. See a, b | aabbaba=abab.