Morphocompletion for #5217 ⟨a, b | aabbaab=baba⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. bababaab ⇒ aabbbaba
2. aabbaab ⇒ baba
3. aabbaaaabbbaba ⇒ babaababaab
4. aabbbabaababaab ⇒ bababaaaabbbaba
5. babaababaababbaab ⇒ aabbaaaabbbabbaba
6. aabbbababaaaabbbaba ⇒ bababbabaababaab
7. aabbbababbabaababaab ⇒ bababbababaaaabbbaba
8. aabbbabaabaababbaab ⇒ baaabbaaaabbbabbaba
9. aabbaaaabbbaaabbbaba ⇒ babaababaabbabaab
10. aabbbaaabbaaaabbbabbaba ⇒ bababbabaabaababbaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab52lf:46,ls:6,rf:44,rs:4
[2/1]ba48lf:42,lp:2,ls:4,rf:48,rp:8,rs:6,lsrp:4,lprs:2
[2/2]aa44lf:36,lp:8,rf:26,rp:2
[2/3]bb28lf:28,rf:19
[3/0]aab40lf:26,lp:8,ls:6,rf:17,rp:2,rs:4,lsrp:2,lprs:4
[3/1]aba26lf:22,ls:4,rf:26,rs:6
[3/2]bab22lf:20,lp:2,rf:27,rp:7
[3/3]baa18lf:18,rf:15,rp:1
[3/4]abb18lf:18,rf:14
[3/5]bba18lf:18,rf:14
[3/6]aaa10lf:10,rf:9,a:2
[4/0]aabb22lf:14,lp:8,rf:8,rp:2
[4/1]baba22lf:16,lp:2,ls:4,rf:21,rp:7,rs:6,re:1,lsrp:4,lprs:2
[4/2]baab18lf:12,ls:6,rf:10,rs:4
[4/3]abaa10lf:10,rf:11,a:1
[4/4]abbb10lf:10,rf:5,a:1
[4/5]bbab10lf:10,rf:11,a:1
[4/6]bbba10lf:10,rf:5,a:1
[5/0]aabbb15lf:10,lp:5,rf:5,rp:1,a:1
[5/1]bbaba13lf:9,ls:4,rf:9,rs:5,a:1
[5/2]abaab12lf:9,ls:3,rf:9,rs:3,a:1
[5/3]babaa10lf:9,lp:1,rf:10,rp:2,a:1
[5/4]abbba10lf:10,rf:5,a:1
[5/5]bbbab8lf:8,rf:5,a:1
[5/6]aabba7lf:4,lp:3,rf:3,rp:1
[6/0]aabbba15lf:10,lp:5,rf:5,rp:1,a:1
[6/1]babaab12lf:8,lp:1,ls:3,rf:8,rp:2,rs:3,a:1
[6/2]bbbaba10lf:7,ls:3,rf:3,rs:3,a:1
[6/3]abbbab8lf:8,rf:5,a:1
[6/4]aabbaa7lf:4,lp:3,rf:2,rp:1
[6/5]abaaba6lf:6,rf:5,a:2
[6/6]abbaab6lf:3,ls:3,rf:1,rs:1
[7/0]aabbbab12lf:8,lp:4,rf:5,rp:1,a:1
[7/1]abbbaba10lf:7,ls:3,rf:3,rs:3,a:1
[7/2]ababaab7lf:4,ls:3,rf:3,rs:2,a:1
[7/3]babaaba6lf:5,lp:1,rf:4,rp:2,a:2
[7/4]aabbaaa5lf:3,lp:2,rf:2,rp:1,a:2
[7/5]abaabab5lf:5,rf:4,a:2
[7/6]aaabbba5lf:5,rf:4,a:2

Considering [length 3 / frequency 0] aab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbaab=baba⟩.