Morphocompletion for #5215 ⟨a, b | aabbaab=baaa⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aabbaab ⇒ baaa
2. aabbbaaa ⇒ baaabaab
3. baaabaabbbaab ⇒ aabbbabaaa
4. baaabaababbaab ⇒ aabbbaabaaa
5. baaabaabbbbaaa ⇒ aabbbabaaabaab
6. baaabaababbbaaa ⇒ aabbbaabaaabaab
7. aabbaaaabbbabaaa ⇒ baaaaaabaabbbaab
8. aabbaaaabbbaabaaa ⇒ baaaaaabaababbaab
9. baaaaaabaabbbaabbbaab ⇒ aabbaaaabbbababaaa
10. baaaaaabaababbaabbbaab ⇒ aabbaaaabbbaababaaa
11. baaaaaabaabbbaababbaab ⇒ aabbaaaabbbabaabaaa
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa69lf:60,lp:4,ls:5,rf:55,rp:7,rs:6,lsrp:2,lprs:1
[2/1]ba43lf:36,lp:7,rf:32,rp:4
[2/2]ab41lf:35,ls:6,rf:33,rs:5
[2/3]bb27lf:27,rf:20
[3/0]aab40lf:30,lp:4,ls:6,rf:26,rp:7,rs:5,lsrp:5,lprs:3
[3/1]baa38lf:31,lp:7,rf:25,rp:4
[3/2]aaa30lf:25,ls:5,rf:23,rs:6
[3/3]bba16lf:16,rf:12
[3/4]abb16lf:16,rf:12
[3/5]aba13lf:13,rf:16,a:1
[3/6]bbb11lf:11,rf:8,a:1
[4/0]baaa26lf:14,lp:7,ls:5,rf:14,rp:4,rs:6,re:1,lsrp:3,lprs:5
[4/1]baab23lf:17,ls:6,rf:11,rs:5
[4/2]aabb16lf:12,lp:4,rf:11,rp:7
[4/3]bbaa15lf:15,rf:8
[4/4]aaba12lf:12,rf:10,a:1
[4/5]aaaa11lf:11,rf:9,a:6
[4/6]bbba10lf:10,rf:8,a:1
[5/0]bbaab16lf:10,ls:6,rf:5,rs:2
[5/1]aabbb10lf:9,lp:1,rf:8,rp:4,a:1
[5/2]bbbaa9lf:9,rf:4,a:1
[5/3]abbba9lf:9,rf:8,a:1
[5/4]baaaa8lf:5,lp:3,rf:5,rp:2,a:6
[5/5]bbaaa8lf:5,ls:3,rf:3,a:1
[5/6]aabaa8lf:8,rf:8,a:1
[6/0]aabbba9lf:8,lp:1,rf:8,rp:4,a:1
[6/1]bbbaab9lf:6,ls:3,rf:4,rs:1,a:2
[6/2]abbbaa8lf:8,rf:4,a:1
[6/3]baaaba8lf:4,lp:4,rf:3,rp:1,a:1
[6/4]aaabaa7lf:7,rf:5,a:1
[6/5]aabaab7lf:7,rf:5,rs:3,a:1
[6/6]abbaab7lf:4,ls:3,rf:1,rs:1
[7/0]abbbaab9lf:6,ls:3,rf:4,rs:1,a:2
[7/1]baaabaa8lf:4,lp:4,rf:3,rp:1,a:1
[7/2]aabbbaa8lf:7,lp:1,rf:4,rp:2,a:1
[7/3]aaabaab7lf:7,rf:5,rs:3,a:1
[7/4]baaaaaa6lf:3,lp:3,rf:2,rp:2,a:6
[7/5]baabbba5lf:5,rf:1,a:2
[7/6]babbaab5lf:3,ls:2,rf:1,rs:1,a:3

Considering [length 5 / frequency 0] bbaab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbaab=baaa⟩.