| Back: | ⟨a, b | aababba=bbaa⟩ |
|---|
Solved by morph:2/2. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aababba ⇒ bbaa |
| 2. | aababbbbaa ⇒ bbabbaa |
| 3. | aababbbbbbaa ⇒ bbabbbbaa |
| 4. | aababbbbabbaa ⇒ bbabbabbaa |
| 5. | aababbbbbbbbaa ⇒ bbabbbbbbaa |
| 6. | aababbbbabbbbaa ⇒ bbabbabbbbaa |
| 7. | aababbbbbbabbaa ⇒ bbabbbbabbaa |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 32 | lf:32,rf:26,rp:7 |
|---|---|---|---|
| [2/1] | aa | 26 | lf:13,lp:7,ls:6,rf:7,rs:7,lprs:7,lsrs:6 |
| [2/2] | ba | 18 | lf:17,ls:1,rf:16 |
| [2/3] | ab | 17 | lf:17,rf:9 |
| [3/0] | bbb | 22 | lf:22,rf:10,a:1 |
| [3/1] | aab | 14 | lf:7,lp:7 |
| [3/2] | baa | 12 | lf:6,ls:6,rf:7,rs:7,lsrs:6 |
| [3/3] | bba | 11 | lf:10,ls:1,rf:16,rp:7,lsrp:1 |
| [3/4] | bab | 10 | lf:10,rf:9 |
| [3/5] | abb | 10 | lf:10,rf:9 |
| [3/6] | aba | 7 | lf:7 |
| [4/0] | bbbb | 15 | lf:15,rf:6,a:1 |
| [4/1] | aaba | 14 | lf:7,lp:7 |
| [4/2] | bbaa | 12 | lf:6,ls:6,rf:7,rp:1,rs:7,re:1,lsrs:6 |
| [4/3] | babb | 10 | lf:10,rf:9 |
| [4/4] | bbba | 7 | lf:7,rf:4,a:1 |
| [4/5] | abbb | 7 | lf:7,rf:4,a:1 |
| [4/6] | abab | 7 | lf:7 |
| [5/0] | aabab | 14 | lf:7,lp:7 |
| [5/1] | bbbbb | 8 | lf:8,rf:2,a:3 |
| [5/2] | bbbaa | 8 | lf:4,ls:4,rf:3,rs:3,lsrs:3,a:1 |
| [5/3] | bbbba | 7 | lf:7,rf:4,a:1 |
| [5/4] | babbb | 7 | lf:7,rf:4,a:1 |
| [5/5] | abbbb | 7 | lf:7,rf:4,a:1 |
| [5/6] | ababb | 7 | lf:7 |
| [6/0] | aababb | 14 | lf:7,lp:7 |
| [6/1] | bbbbaa | 8 | lf:4,ls:4,rf:3,rs:3,lsrs:3,a:1 |
| [6/2] | babbbb | 7 | lf:7,rf:4,a:1 |
| [6/3] | ababbb | 6 | lf:6,a:1 |
| [6/4] | bbbbbb | 5 | lf:5,rf:1,a:3 |
| [6/5] | abbbba | 4 | lf:4,rf:3,a:1 |
| [6/6] | babbaa | 4 | lf:2,ls:2,rf:3,rs:3,lsrs:2,a:1 |
| [7/0] | aababbb | 12 | lf:6,lp:6,a:1 |
| [7/1] | ababbbb | 6 | lf:6,a:1 |
| [7/2] | bbbbbaa | 4 | lf:2,ls:2,rf:1,rs:1,lsrs:1,a:3 |
| [7/3] | babbbba | 4 | lf:4,rf:3,a:1 |
| [7/4] | bbabbaa | 4 | lf:2,ls:2,rf:3,rp:1,rs:3,re:1,lsrs:2,a:1 |
| [7/5] | abbbbaa | 4 | lf:2,ls:2,rf:2,rs:2,lsrs:1,a:1 |
| [7/6] | bbbbbba | 3 | lf:3,rf:1,a:3 |
Considering [length 2 / frequency 2] ba=c.
Rewriting system is complete. See ⟨a, b | aababba=bbaa⟩.