Morphocompletion for #5196 ⟨a, b | aababba=abab⟩

Solved by morph:2/0,2/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababba ⇒ abab
2. aaababbbab ⇒ ababbba
3. ababbabba ⇒ aababbbab
4. ababababba ⇒ ababbab
5. ababbababba ⇒ ababbbab
6. aababababbbab ⇒ ababbbabba
7. ababaababbbab ⇒ ababbabbba
8. aababbbabbba ⇒ ababababbbab
9. ababbabababba ⇒ ababbabbab
...

Collecting factors up to length 7 / frequency 3:

[2/0]ab42lf:34,lp:5,ls:3,rf:28,rp:8,rs:6,lprp:4,lsrp:3,lprs:4
[2/1]ba37lf:31,ls:6,rf:22,rs:3
[2/2]bb18lf:18,rf:17
[3/0]bab27lf:24,ls:3,rf:19,rs:6
[3/1]aba23lf:18,lp:5,rf:11,rp:8,lprp:4
[3/2]bba19lf:13,ls:6,rf:11,rs:3
[4/0]abab22lf:17,lp:5,rf:11,rp:8,rs:1,re:1,lprp:4
[4/1]babb13lf:13,rf:11
[4/2]abba13lf:8,ls:5,rf:5,rs:1
[5/0]ababb14lf:11,lp:3,rf:8,rp:6,lprp:2
[5/1]babba13lf:8,ls:5,rf:5,rs:1
[5/2]ababa8lf:6,lp:2,rf:2,rp:1,a:1
[6/0]ababba14lf:7,lp:3,ls:4,rf:3,rp:3,lprp:1,lsrp:2
[6/1]abbbab7lf:4,ls:3,rf:4,rs:3,a:4
[6/2]babbba6lf:5,ls:1,rf:6,rs:2,a:4

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. accba ⇒ cc
3. accccba ⇒ ccb
4. ccbc ⇒ ccccba
5. aaccccccbac ⇒ ccccccbaa
6. aaaaccaccccccbac ⇒ ccccccbaaa
7. ccccccbaca ⇒ aaccaccccccbac
8. ccccccbaaca ⇒ aaaaccaccaccccccbac
9. ccccccbacca ⇒ aaccaccaccccccbac
10. ccbb ⇒ accccccba
11. aaccaccccccbacb ⇒ ccccccbacc
12. aaccaccaccccccbacb ⇒ ccccccbaccc
13. ccccbacba ⇒ accccccbac
14. ccccccbaacba ⇒ aaccccccccbac
15. ccccbacccba ⇒ accccccbacb
16. ccccccbaacccba ⇒ aaccccccccbacb
17. ccccbacbc ⇒ accccccbacb
18. ccccccbaacbc ⇒ aaccccccccbacb
19. ccbaccccccbac ⇒ accccccbacccccbaa
20. ccccbacbb ⇒ ccbaccccccba
...

Collecting factors up to length 6 / frequency 5:

[2/0]cc96lf:83,lp:13,rf:104,rp:8,rs:3,re:1,lprp:2,a:2
[2/1]cb31lf:29,ls:2,rf:24,rs:5,a:2
[2/2]ac31lf:26,lp:2,ls:3,rf:29,rp:5,rs:5,lsrp:1,a:2
[2/3]ba28lf:22,ls:6,rf:19,rs:3,a:2
[2/4]aa14lf:10,lp:4,rf:12,rp:6,rs:3,lprs:2,a:10
[3/0]ccc66lf:56,lp:10,rf:76,rp:5,rs:1,a:3
[3/1]cba28lf:22,ls:6,rf:19,rs:3,a:2
[3/2]ccb25lf:22,lp:3,rf:20,rp:2,rs:1,re:1,a:2
[3/3]acc16lf:14,lp:2,rf:20,rp:5,rs:1,a:2
[3/4]bac15lf:12,ls:3,rf:13,rs:5,a:6
[4/0]cccc48lf:38,lp:10,rf:57,rp:5,a:3
[4/1]ccba25lf:20,lp:1,ls:4,rf:19,rp:1,rs:3,a:2
[4/2]cccb18lf:18,rf:18,a:3
[4/3]cbac15lf:12,ls:3,rf:13,rs:5,a:6
[4/4]accc9lf:8,lp:1,rf:14,rp:5,rs:1,a:3
[5/0]ccccc28lf:22,lp:6,rf:39,rp:4,a:5
[5/1]cccba21lf:18,ls:3,rf:18,rs:3,a:3
[5/2]ccccb20lf:16,lp:4,rf:18,rp:1,a:3
[5/3]ccbac16lf:12,lp:1,ls:3,rf:13,rp:1,rs:5,a:6
[5/4]cbacb7lf:5,ls:2,rf:4,rs:4,a:6

Considering [length 2 / frequency 0] cc=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. dc ⇒ cd
2. cc ⇒ d
3. ab ⇒ c
4. adba ⇒ d
5. addba ⇒ db
6. adbd ⇒ ddba
7. aaddbd ⇒ dddbaa
8. ddbda ⇒ aadaddbd
9. dbc ⇒ ddba
10. ddbac ⇒ dbd
11. dddbaac ⇒ aadddbad
12. dbb ⇒ adddba
13. aadaddbdb ⇒ dddbad
14. aadadaddbdb ⇒ ddbdd
15. dbdba ⇒ addbd
16. dbddba ⇒ addbdb
17. dbdbd ⇒ adaddbdb
...

Collecting factors up to length 6 / frequency 5:

[2/0]db26lf:19,lp:5,ls:2,rf:15,rp:2,rs:3,re:1,lprs:2,a:3
[2/1]bd12lf:9,ls:3,rf:6,rs:3,a:6
[2/2]dd12lf:9,lp:3,rf:16,rp:5,rs:1,a:6
[2/3]ad12lf:9,lp:3,rf:10,rp:4,rs:2,a:3
[2/4]ba10lf:6,ls:4,rf:6,rs:3,a:3
[3/0]dbd15lf:9,lp:3,ls:3,rf:6,rp:1,rs:3,re:1,lprs:1,a:6
[3/1]dba10lf:6,ls:4,rf:6,rs:3,a:3
[3/2]ddb10lf:8,lp:2,rf:11,rp:3,a:6
[3/3]bdb6lf:4,ls:2,rf:2,rs:2,a:11
[3/4]aad6lf:3,lp:3,rf:2,rp:2,a:14
[4/0]dbdb8lf:4,lp:2,ls:2,rf:2,rs:2,lprs:1,a:11
[4/1]ddba7lf:4,lp:1,ls:2,rf:6,rp:2,rs:3,re:2,a:6
[4/2]ddbd6lf:4,lp:1,ls:1,rf:5,rp:1,rs:2,lprs:1,a:11
[4/3]addb5lf:4,lp:1,rf:4,rp:2,a:9
[4/4]aada4lf:2,lp:2,rf:1,rp:1,a:19
[5/0]ddbdb4lf:2,ls:2,rf:2,rs:2,a:12
[5/1]addbd4lf:3,ls:1,rf:4,rp:2,rs:2,re:1,a:11
[5/2]aadad4lf:2,lp:2,rf:1,rp:1,a:19
[5/3]bddba2lf:1,ls:1,a:13
[5/4]dbddb2lf:1,lp:1,a:13

Considering [length 4 / frequency 0] dbdb=e.

Step 4

Rewriting system is complete. See ⟨a, b | aababba=abab⟩.