Morphocompletion for #5196 ⟨a, b | aababba=abab

Solved by morph:2/0,2/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababba ⇒ abab
2. aaababbbab ⇒ ababbba
3. ababbabba ⇒ aababbbab
4. ababababba ⇒ ababbab
5. ababbababba ⇒ ababbbab
6. aababababbbab ⇒ ababbbabba
7. ababaababbbab ⇒ ababbabbba
8. aababbbabbba ⇒ ababababbbab
9. ababbabababba ⇒ ababbabbab
...

Collecting factors up to length 7, frequency 3:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb
Length 3:[3/0] bab, [3/1] aba, [3/2] bba
Length 4:[4/0] abab, [4/1] babb, [4/2] abba
Length 5:[5/0] ababb, [5/1] babba, [5/2] ababa
Length 6:[6/0] ababba, [6/1] abbbab, [6/2] babbba

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. accba ⇒ cc
3. accccba ⇒ ccb
4. ccbc ⇒ ccccba
5. aaccccccbac ⇒ ccccccbaa
6. ccccccbaaa ⇒ aaaaccaccccccbac
7. ccccccbaca ⇒ aaccaccccccbac
8. ccccccbaaca ⇒ aaaaccaccaccccccbac
9. ccccccbacca ⇒ aaccaccaccccccbac
10. ccbb ⇒ accccccba
11. aaccaccccccbacb ⇒ ccccccbacc
12. aaccaccaccccccbacb ⇒ ccccccbaccc
13. ccccbacba ⇒ accccccbac
14. ccccccbaacba ⇒ aaccccccccbac
15. ccccbacccba ⇒ accccccbacb
16. ccccccbaacccba ⇒ aaccccccccbacb
17. ccccbacbc ⇒ accccccbacb
18. ccccccbaacbc ⇒ aaccccccccbacb
19. ccbaccccccbac ⇒ accccccbacccccbaa
20. ccccbacbb ⇒ ccbaccccccba
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] cc, [2/1] cb, [2/2] ba, [2/3] ac, [2/4] aa
Length 3:[3/0] ccc, [3/1] cba, [3/2] ccb, [3/3] acc, [3/4] bac
Length 4:[4/0] cccc, [4/1] ccba, [4/2] cccb, [4/3] cbac, [4/4] accc
Length 5:[5/0] ccccc, [5/1] cccba, [5/2] ccccb, [5/3] ccbac, [5/4] cbacb

Considering [length 2 / frequency 0] cc=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. dc ⇒ cd
2. cc ⇒ d
3. ab ⇒ c
4. adba ⇒ d
5. addba ⇒ db
6. adbd ⇒ ddba
7. dbc ⇒ ddba
8. dddbaa ⇒ aaddbd
9. ddbda ⇒ aadaddbd
10. ddbac ⇒ dbd
11. dbb ⇒ adddba
12. aaddbdb ⇒ ddbd
13. aadaddbdb ⇒ dddbad
14. dbdba ⇒ addbd
15. dbddba ⇒ addbdb
16. dbdbd ⇒ adaddbdb
17. aaddbddbd ⇒ dddbdb
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] db, [2/1] bd, [2/2] dd, [2/3] ba, [2/4] ad
Length 3:[3/0] dbd, [3/1] ddb, [3/2] dba, [3/3] bdb, [3/4] aad
Length 4:[4/0] dbdb, [4/1] ddbd, [4/2] ddba, [4/3] addb, [4/4] aadd
Length 5:[5/0] ddbdb, [5/1] aaddb, [5/2] dbddb, [5/3] addbd, [5/4] bddbd

Considering [length 4 / frequency 0] dbdb=e.

Step 4

Rewriting system is complete. See a, b | aababba=abab.