Morphocompletion for #5166 ⟨a, b | aababaa=aaab

Solved by morph:6/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababaa ⇒ aaab
2. aaabbabaa ⇒ aaabab
3. aaabababaa ⇒ aaabaab
4. aaababbabaa ⇒ aaababab
5. aaababababaa ⇒ aaaabb
6. aaabaabbabaa ⇒ aaabaabab
7. aaaabbbabaa ⇒ aaaabbab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aba, [3/1] baa, [3/2] aaa, [3/3] bab
Length 4:[4/0] abaa, [4/1] aaab, [4/2] baba, [4/3] abab
Length 5:[5/0] babaa, [5/1] aaaba, [5/2] ababa, [5/3] aabab
Length 6:[6/0] bbabaa, [6/1] aaabab, [6/2] ababaa, [6/3] aababa

Considering [length 6 / frequency 0] bbabaa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaab ⇒ aaacaa
2. aaacaacaa ⇒ aaaac
3. caab ⇒ cacaa
4. caaab ⇒ caacaa
5. aaaacab ⇒ aaacaaac
6. aaabac ⇒ aaacab
7. aababaa ⇒ aaab
8. aaabab ⇒ aaac
9. aaabaab ⇒ aaacabaa
10. cacaacaa ⇒ caac
11. caaccaa ⇒ cacaaac
12. caacaacaa ⇒ caaac
13. caacab ⇒ cacaaac
14. cabac ⇒ cacab
15. cbabaa ⇒ cab
16. cabab ⇒ cac
17. cabaab ⇒ cacabaa
18. bbabaa ⇒ c
19. caacbac ⇒ caacccaa
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ca, [2/2] ab, [2/3] ac, [2/4] ba, [2/5] cb, [2/6] bb
Length 3:[3/0] caa, [3/1] aab, [3/2] aaa, [3/3] cab, [3/4] aba, [3/5] aac, [3/6] baa
Length 4:[4/0] caac, [4/1] aaab, [4/2] acaa, [4/3] abaa, [4/4] aaca, [4/5] caba, [4/6] abab
Length 5:[5/0] aacaa, [5/1] caaca, [5/2] babaa, [5/3] aaaba, [5/4] aabab, [5/5] abaab, [5/6] aacab

Considering [length 3 / frequency 0] caa=d.

Step 3

Rewriting system is complete. See a, b | aababaa=aaab.