Morphocompletion for #5141 ⟨a, b | aabaaba=baaa⟩

Solved by morph:6/2,3/3. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaaba ⇒ baaa
2. aabbaaa ⇒ baaaaba
3. aabbaabaaa ⇒ baabaaaaba
4. aabbbaaaaa ⇒ bbaaaaaaba
5. baaaababaaba ⇒ aabbabaaa
6. baaaababbaaa ⇒ aabbabaaaaba
7. aabaabbabaaa ⇒ baababaaa
8. aabbaababaaa ⇒ baaaabbabaaa
9. aabaabbababaaa ⇒ baabababaaa
...

Collecting factors up to length 7 / frequency 4:

[2/0]aa49lf:35,lp:7,ls:7,rf:32,rp:2,rs:5,lsrp:1,lprs:4,lsrs:3
[2/1]ba27lf:23,lp:2,ls:2,rf:23,rp:6,rs:4,lsrp:1,lprs:1
[2/2]ab21lf:21,rf:16
[2/3]bb8lf:8,rf:4,rp:1,a:1
[3/0]aab22lf:15,lp:7,rf:10,rp:2
[3/1]aaa20lf:13,ls:7,rf:17,rs:5,lsrs:3
[3/2]baa17lf:15,lp:2,rf:13,rp:6
[3/3]aba16lf:14,ls:2,rf:13,rs:4
[4/0]baaa17lf:9,lp:2,ls:6,rf:10,rp:3,rs:5,re:1,lsrp:2,lprs:1,lsrs:3
[4/1]aaba14lf:9,lp:3,ls:2,rf:7,rs:4
[4/2]aabb10lf:6,lp:4,rf:3,rp:2,a:1
[4/3]abaa8lf:8,rf:6
[5/0]aabba8lf:5,lp:3,rf:3,rp:2,a:1
[5/1]abaaa8lf:4,ls:4,rf:6,rs:4,lsrs:3,a:2
[5/2]aabaa7lf:4,lp:3,rf:1
[5/3]baaba6lf:4,ls:2,rf:3,rp:3
[6/0]babaaa6lf:3,ls:3,rf:5,rs:4,lsrs:3,a:2
[6/1]aabbaa6lf:3,lp:3,a:1
[6/2]aabaab6lf:3,lp:3
[6/3]abbaaa4lf:2,ls:2,a:1

Considering [length 6 / frequency 2] aabaab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aacca ⇒ caaa
2. aaccc ⇒ caac
3. aabc ⇒ caab
4. aacbac ⇒ cac
5. baaa ⇒ ca
6. baac ⇒ cc
7. bcac ⇒ ccbac
8. bcaaa ⇒ ccca
9. bcaac ⇒ cccc
10. bacac ⇒ cacbac
11. bccac ⇒ ccccbac
12. bacaaa ⇒ cacca
13. bccaaa ⇒ ccccca
14. bacaac ⇒ caccc
15. bccaac ⇒ cccccc
16. aabaab ⇒ c
17. cabaab ⇒ bac
18. cabcaab ⇒ bacc
19. bacaab ⇒ cabc
20. baabac ⇒ cbac
...

Collecting factors up to length 6 / frequency 7:

[2/0]aa31lf:22,lp:5,ls:4,rf:4,rs:1,lprs:1,a:1
[2/1]ac25lf:16,ls:9,rf:11,rs:7,lsrs:5,a:5
[2/2]ba18lf:11,lp:7,rf:6,rp:2,a:1
[2/3]ca17lf:14,lp:2,ls:1,rf:12,rp:9,rs:4,re:1,lsrp:1,a:2
[2/4]bc15lf:8,lp:6,ls:1,rf:1,rs:1,a:3
[2/5]ab13lf:9,ls:4,rf:2,rs:1,a:1
[2/6]cc7lf:6,ls:1,rf:23,rp:7,rs:5,re:1,a:6
[3/0]aac14lf:7,lp:3,ls:4,rf:1,rs:1,lprs:1,a:6
[3/1]aab13lf:7,lp:2,ls:4,rf:1,rs:1,lprs:10,a:1
[3/2]bac12lf:6,lp:4,ls:2,rf:6,rp:2,rs:5,re:1,lprs:1,lsrs:1,a:5
[3/3]baa8lf:5,lp:3,a:1
[3/4]caa8lf:8,rf:3,rp:3,a:3
[3/5]aaa8lf:4,ls:4,rf:1,rs:1,a:2
[3/6]bca7lf:4,lp:3,a:10
[4/0]baca8lf:4,lp:4,a:8
[4/1]baab6lf:3,lp:1,ls:2,a:1
[4/2]bcca6lf:3,lp:3,a:11
[4/3]caac6lf:3,ls:3,rf:1,rp:1,rs:1,re:1,a:7
[4/4]caaa6lf:3,ls:3,rf:1,rp:1,rs:1,re:1,a:13
[4/5]bcaa5lf:3,lp:2,a:10
[4/6]caab4lf:2,ls:2,rf:1,rp:1,rs:1,re:1,a:3
[5/0]bacaa6lf:3,lp:3,a:8
[5/1]abaab4lf:2,ls:2,a:1
[5/2]bccaa4lf:2,lp:2,a:11
[5/3]baaba2lf:1,lp:1,a:15
[5/4]bcaab2lf:1,ls:1,a:14
[5/5]acbac2lf:1,ls:1,rf:1,rs:1,a:22
[5/6]aabac2lf:1,ls:1,a:15

Considering [length 3 / frequency 3] baa=d.

Step 3

Rewriting system is complete. See ⟨a, b | aabaaba=baaa⟩.