Morphocompletion for #5141 ⟨a, b | aabaaba=baaa

Solved by morph:6/2,3/3. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaaba ⇒ baaa
2. aabbaaa ⇒ baaaaba
3. aabbaabaaa ⇒ baabaaaaba
4. aabbbaaaaa ⇒ bbaaaaaaba
5. baaaababaaba ⇒ aabbabaaa
6. baaaababbaaa ⇒ aabbabaaaaba
7. aabaabbabaaa ⇒ baababaaa
8. aabbaababaaa ⇒ baaaabbabaaa
9. aabaabbababaaa ⇒ baabababaaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aab, [3/1] aaa, [3/2] baa, [3/3] aba
Length 4:[4/0] baaa, [4/1] aaba, [4/2] aabb, [4/3] abaa
Length 5:[5/0] aabba, [5/1] abaaa, [5/2] aabaa, [5/3] baaba
Length 6:[6/0] babaaa, [6/1] aabbaa, [6/2] aabaab, [6/3] abbaaa

Considering [length 6 / frequency 2] aabaab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aacca ⇒ caaa
2. aaccc ⇒ caac
3. aabc ⇒ caab
4. aacbac ⇒ cac
5. baaa ⇒ ca
6. baac ⇒ cc
7. bcac ⇒ ccbac
8. bcaaa ⇒ ccca
9. bcaac ⇒ cccc
10. bacac ⇒ cacbac
11. bccac ⇒ ccccbac
12. bacaaa ⇒ cacca
13. bccaaa ⇒ ccccca
14. bacaac ⇒ caccc
15. bccaac ⇒ cccccc
16. aabaab ⇒ c
17. cabaab ⇒ bac
18. cabcaab ⇒ bacc
19. bacaab ⇒ cabc
20. baabac ⇒ cbac
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ac, [2/2] ba, [2/3] ca, [2/4] bc, [2/5] ab, [2/6] cc
Length 3:[3/0] aac, [3/1] aab, [3/2] bac, [3/3] baa, [3/4] caa, [3/5] aaa, [3/6] bca
Length 4:[4/0] baca, [4/1] baab, [4/2] bcca, [4/3] caac, [4/4] caaa, [4/5] bcaa, [4/6] caab
Length 5:[5/0] bacaa, [5/1] abaab, [5/2] bccaa, [5/3] baaba, [5/4] bcaab, [5/5] acbac, [5/6] aabac

Considering [length 3 / frequency 3] baa=d.

Step 3

Rewriting system is complete. See a, b | aabaaba=baaa.