Morphocompletion for #5138 ⟨a, b | aabaaba=abab⟩

Back:⟨a, b | aabaaba=abab⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaaba ⇒ abab
2. aababab ⇒ abababa
3. abababaaba ⇒ ababbab
4. aababbab ⇒ abababaaaba
5. ababbabaaba ⇒ ababbbab
6. ababababab ⇒ ababbababa
7. aababbbab ⇒ abababaaabaaaba
8. ababbbabaaba ⇒ ababbbbab
9. ababbababab ⇒ ababbbababa
10. ababbababaaba ⇒ ababbabbab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] aab, [3/3] abb, [3/4] bba, [3/5] baa, [3/6] bbb
Length 4:[4/0] abab, [4/1] aaba, [4/2] baba, [4/3] bbab, [4/4] babb, [4/5] baab, [4/6] abaa
Length 5:[5/0] babab, [5/1] ababb, [5/2] ababa, [5/3] baaba, [5/4] aabab, [5/5] abbab, [5/6] abaab
Length 6:[6/0] ababab, [6/1] abaaba, [6/2] ababba, [6/3] babbab, [6/4] bababa, [6/5] aababb, [6/6] babaab
Length 7:[7/0] ababbab, [7/1] babaaba, [7/2] bababab, [7/3] abababa, [7/4] babbbab, [7/5] ababbba, [7/6] babbaba

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabaaba=abab⟩.