| Back: | ⟨a, b | aabaaba=abab⟩ |
|---|
Solved by morph:2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabaaba ⇒ abab |
| 2. | aababab ⇒ abababa |
| 3. | abababaaba ⇒ ababbab |
| 4. | aababbab ⇒ abababaaaba |
| 5. | ababbabaaba ⇒ ababbbab |
| 6. | ababababab ⇒ ababbababa |
| 7. | aababbbab ⇒ abababaaabaaaba |
| 8. | ababbbabaaba ⇒ ababbbbab |
| 9. | ababbababab ⇒ ababbbababa |
| 10. | ababbababaaba ⇒ ababbabbab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 49 | lf:38,lp:6,ls:5,rf:35,rp:10,rs:5,lprp:6,lsrp:5,lprs:4 |
|---|---|---|---|
| [2/1] | ba | 38 | lf:33,ls:5,rf:30,rs:5 |
| [2/2] | aa | 13 | lf:9,lp:4,rf:6 |
| [2/3] | bb | 8 | lf:8,rf:11,a:2 |
| [3/0] | aba | 38 | lf:27,lp:6,ls:5,rf:23,rp:10,rs:5,lprp:6,lsrp:5,lprs:2 |
| [3/1] | bab | 28 | lf:23,ls:5,rf:22,rs:5 |
| [3/2] | aab | 13 | lf:9,lp:4,rf:3 |
| [3/3] | abb | 6 | lf:6,rf:7,a:2 |
| [3/4] | bba | 6 | lf:6,rf:7,a:2 |
| [3/5] | baa | 5 | lf:5,rf:3 |
| [3/6] | bbb | 2 | lf:2,rf:4,a:7 |
| [4/0] | abab | 26 | lf:17,lp:6,ls:3,rf:15,rp:10,rs:1,re:1,lprp:6,lsrp:3 |
| [4/1] | aaba | 18 | lf:9,lp:4,ls:5,rf:3,rs:2,lprs:2 |
| [4/2] | baba | 12 | lf:12,rf:10,rs:3,a:1 |
| [4/3] | bbab | 8 | lf:6,ls:2,rf:7,rs:4,a:2 |
| [4/4] | babb | 6 | lf:6,rf:7,a:2 |
| [4/5] | baab | 5 | lf:5 |
| [4/6] | abaa | 5 | lf:5,rf:3 |
| [5/0] | babab | 11 | lf:8,ls:3,rf:5,a:1 |
| [5/1] | ababb | 10 | lf:6,lp:4,rf:6,rp:6,lprp:4,a:2 |
| [5/2] | ababa | 10 | lf:8,lp:2,rf:8,rp:3,rs:3,lprs:1,a:1 |
| [5/3] | baaba | 10 | lf:5,ls:5 |
| [5/4] | aabab | 6 | lf:3,lp:3,a:1 |
| [5/5] | abbab | 5 | lf:4,ls:1,rf:4,rs:2,a:2 |
| [5/6] | abaab | 5 | lf:5 |
| [6/0] | ababab | 11 | lf:6,lp:2,ls:3,rf:3,rp:3,lsrp:10,a:1 |
| [6/1] | abaaba | 10 | lf:5,ls:5 |
| [6/2] | ababba | 7 | lf:4,lp:3,rf:3,rp:3,lprp:1,a:2 |
| [6/3] | babbab | 5 | lf:4,ls:1,rf:4,rs:2,a:2 |
| [6/4] | bababa | 5 | lf:5,rf:5,rs:3,a:1 |
| [6/5] | aababb | 4 | lf:2,lp:2,a:3 |
| [6/6] | babaab | 4 | lf:4,a:2 |
| [7/0] | ababbab | 8 | lf:4,lp:3,ls:1,rf:3,rp:3,rs:1,re:1,lprp:1,a:2 |
| [7/1] | babaaba | 8 | lf:4,ls:4,a:2 |
| [7/2] | bababab | 5 | lf:3,ls:2,a:4 |
| [7/3] | abababa | 5 | lf:3,lp:2,rf:3,rp:3,rs:1,re:1,a:1 |
| [7/4] | babbbab | 3 | lf:2,ls:1,rf:2,rs:1,a:7 |
| [7/5] | ababbba | 3 | lf:2,lp:1,rf:2,rp:2,a:7 |
| [7/6] | babbaba | 3 | lf:3,rf:1,a:4 |
Considering [length 2 / frequency 0] ab=c.
Rewriting system is complete. See ⟨a, b | aabaaba=abab⟩.