Morphocompletion for #5137 ⟨a, b | aabaaba=abaa

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaaba ⇒ aababaa
2. aabaaba ⇒ abaa
3. ababaaaaba ⇒ aabababaaa
4. abaaaababa ⇒ aaabababaa
5. aaababaabaa ⇒ abaaaaba
6. ababaabaaaaba ⇒ aabababaabaaa
7. ababaaaaababa ⇒ aaababababaaa
8. abaaaaabababa ⇒ aaaababababaa
9. aaababaababaaa ⇒ abaabaaaaba
10. aaaabababaabaa ⇒ abaaaaababa
11. aabababaaaaaba ⇒ aaababababaaaa
12. aaababaababaabaaa ⇒ ababaaaaaba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab
Length 3:[3/0] aba, [3/1] aaa, [3/2] aab, [3/3] baa, [3/4] bab
Length 4:[4/0] aaba, [4/1] abaa, [4/2] abab, [4/3] baba, [4/4] aaab, [4/5] aaaa, [4/6] baaa
Length 5:[5/0] ababa, [5/1] aaaba, [5/2] abaaa, [5/3] aabab, [5/4] babaa, [5/5] aaaab, [5/6] aabaa
Length 6:[6/0] aababa, [6/1] ababaa, [6/2] aaaaba, [6/3] aaabab, [6/4] abaaaa, [6/5] abaaba, [6/6] baabaa
Length 7:[7/0] aaababa, [7/1] ababaaa, [7/2] ababaab, [7/3] abaabaa, [7/4] babaaba, [7/5] aaaabab, [7/6] baaaaba

Considering [length 2 / frequency 0] aa=c.

Step 2

Rewriting system is complete. See a, b | aabaaba=abaa.