Morphocompletion for #5134 ⟨a, b | aabaaba=aaab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaaba ⇒ aaab
2. aabaaab ⇒ aaababa
3. aabaaaab ⇒ aaaabbaa
4. aaababaaba ⇒ aaabaab
5. aaaabbaaba ⇒ aaaabab
6. aaababaaab ⇒ aaaabba
7. aaaabbaaab ⇒ aaaabababa
8. aabaaaaabb ⇒ aaaaabbaba
9. aaaabaabbaaa ⇒ aabaaaaab
10. aaaabaabbaaba ⇒ aaaaabb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aab, [3/1] aaa, [3/2] aba, [3/3] baa, [3/4] abb, [3/5] bba, [3/6] bab
Length 4:[4/0] aaba, [4/1] aaab, [4/2] aaaa, [4/3] abaa, [4/4] baaa, [4/5] aabb, [4/6] baab
Length 5:[5/0] aaaab, [5/1] aabaa, [5/2] baaba, [5/3] aaaba, [5/4] baaab, [5/5] abaaa, [5/6] aaabb
Length 6:[6/0] aabaaa, [6/1] aaaabb, [6/2] aaaaba, [6/3] aaabab, [6/4] aabaab, [6/5] abaaab, [6/6] abaaba
Length 7:[7/0] aaaabaa, [7/1] aabaaaa, [7/2] aaaabba, [7/3] aaababa, [7/4] abbaaba, [7/5] aabbaaa, [7/6] aaaaabb

Considering [length 3 / frequency 0] aab=c.

Step 2

Rewriting system is complete. See a, b | aabaaba=aaab.