Morphocompletion for #5127 ⟨a, b | aabaaab=baba⟩

Back:⟨a, b | aabaaab=baba⟩

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: workTotalLimit

#Rule
1. baba ⇒ aabaaab
2. aabaaabba ⇒ baaabaaab
3. aabaaaaabaaabaabba ⇒ babbaaabaaab
4. aabaaaaabaaabaaaabaaabaabba ⇒ babbabbaaabaaab
5. aabaaaaabaaabaaaabaaabaaaabaaabaabba ⇒ babbabbabbaaabaaab
6. aabaaaaabaaabaaaabaaabaaaabaaabaaaabaaabaabba ⇒ babbabbabbabbaaabaaab
7. aabaaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaabba ⇒ babbabbabbabbabbaaabaaab
8. aabaaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaabba ⇒ babbabbabbabbabbabbaaabaaab
9. aabaaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaabba ⇒ babbabbabbabbabbabbabbaaabaaab
10. aabaaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaabba ⇒ babbabbabbabbabbabbabbabbaaabaaab
11. aabaaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaabba ⇒ babbabbabbabbabbabbabbabbabbaaabaaab
12. aabaaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaabba ⇒ babbabbabbabbabbabbabbabbabbabbaaabaaab
13. aabaaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaabba ⇒ babbabbabbabbabbabbabbabbabbabbabbaaabaaab
14. aabaaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaaaabaaabaabba ⇒ babbabbabbabbabbabbabbabbabbabbabbabbaaabaaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] aba, [3/3] baa, [3/4] bba, [3/5] abb, [3/6] bab
Length 4:[4/0] aaba, [4/1] abaa, [4/2] baaa, [4/3] aaab, [4/4] aaaa, [4/5] abba, [4/6] aabb
Length 5:[5/0] aabaa, [5/1] abaaa, [5/2] aaaba, [5/3] baaab, [5/4] baaaa, [5/5] aaaab, [5/6] aabba
Length 6:[6/0] aabaaa, [6/1] aaabaa, [6/2] abaaab, [6/3] baaaba, [6/4] abaaaa, [6/5] aaaaba, [6/6] baaaab
Length 7:[7/0] aaabaaa, [7/1] aabaaaa, [7/2] aabaaab, [7/3] baaabaa, [7/4] abaaaba, [7/5] aaaabaa, [7/6] baaaaba

Considering [length 6 / frequency 0] aabaaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabaaab=baba⟩.