Morphocompletion for #5077 ⟨a, b | aaabbaa=baaa

Solved by morph:3/2,5/3. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbaa ⇒ baaa
2. aaabbbaaa ⇒ babaaa
3. aaabbabaaa ⇒ baabaaa
4. aaabbbbaaa ⇒ babbaaa
5. aaabbabbaaa ⇒ baabbaaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab
Length 3:[3/0] aaa, [3/1] bba, [3/2] abb, [3/3] baa
Length 4:[4/0] aaab, [4/1] baaa, [4/2] bbaa, [4/3] aabb
Length 5:[5/0] aaabb, [5/1] bbaaa, [5/2] abbaa, [5/3] aabba
Length 6:[6/0] aaabba, [6/1] bbbaaa, [6/2] aaabbb, [6/3] aabbab

Considering [length 3 / frequency 2] abb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaacacaa ⇒ caaa
2. aaacacac ⇒ caac
3. aaacaccaaa ⇒ cacaaa
4. aaacaccaac ⇒ cacaac
5. aaacacccaaa ⇒ caccaaa
6. aaacacccaac ⇒ caccaac
7. baaa ⇒ aacaa
8. baac ⇒ aacac
9. bcaaa ⇒ aacaacacaa
10. bacaaa ⇒ aaccaaa
11. bcaac ⇒ aacaacacac
12. bacaac ⇒ aaccaac
13. baccaaa ⇒ aacccaaa
14. bcacaaa ⇒ aacaacaccaaa
15. bacacaaa ⇒ aaccacaaa
16. baccaac ⇒ aacccaac
17. bacacaac ⇒ aaccacaac
18. bacccaaa ⇒ aaccccaaa
19. bacccaac ⇒ aaccccaac
20. abb ⇒ c
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ac, [2/2] ca, [2/3] ba, [2/4] cc, [2/5] bc, [2/6] bb
Length 3:[3/0] aaa, [3/1] aac, [3/2] caa, [3/3] bac, [3/4] aca, [3/5] cac, [3/6] cca
Length 4:[4/0] caaa, [4/1] caac, [4/2] aaac, [4/3] acac, [4/4] bacc, [4/5] baca, [4/6] ccaa
Length 5:[5/0] aaaca, [5/1] ccaac, [5/2] ccaaa, [5/3] aacac, [5/4] acaaa, [5/5] cacaa, [5/6] baccc

Considering [length 5 / frequency 3] aacac=d.

Step 3

Rewriting system is complete. See a, b | aaabbaa=baaa.