Morphocompletion for #5074 ⟨a, b | aaabbaa=abab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aaabbaa ⇒ abab
2. abababbaa ⇒ aaabbabab
3. ababaabbaa ⇒ ababbab
4. ababbababbaa ⇒ ababaabbabab
5. ababbabaabbaa ⇒ ababbabbab
6. ababbabbababbaa ⇒ ababbabaabbabab
7. ababbabbabaabbaa ⇒ ababbabbabbab
8. ababbabbabbababbaa ⇒ ababbabbabaabbabab
9. ababbabbabbabaabbaa ⇒ ababbabbabbabbab
10. ababbabbabbabbababbaa ⇒ ababbabbabbabaabbabab
11. ababbabbabbabbabaabbaa ⇒ ababbabbabbabbabbab
12. ababbabbabbabbabbababbaa ⇒ ababbabbabbabbabaabbabab
13. ababbabbabbabbabbabaabbaa ⇒ ababbabbabbabbabbabbab
14. ababbabbabbabbabbabbababbaa ⇒ ababbabbabbabbabbabaabbabab
15. ababbabbabbabbabbabbabaabbaa ⇒ ababbabbabbabbabbabbabbab
16. ababbabbabbabbabbabbabbabaabbaa ⇒ ababbabbabbabbabbabbabbabbab
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab110lf:95,lp:15,rf:102,rp:15,rs:16,lprp:14,lprs:15
[2/1]ba95lf:95,rf:86
[2/2]bb65lf:65,rf:58
[2/3]aa43lf:26,lp:1,ls:16,rf:8,rp:1,lsrp:1
[3/0]bab71lf:71,rf:80,rs:16
[3/1]bba65lf:65,rf:58
[3/2]abb65lf:65,rf:58
[3/3]aba45lf:30,lp:15,rf:28,rp:15,lprp:14
[3/4]baa40lf:24,ls:16,rf:6
[3/5]aab9lf:9,rf:7
[3/6]aaa2lf:1,lp:1,rf:1,rp:1
[4/0]abba65lf:65,rf:58
[4/1]babb56lf:56,rf:51,a:1
[4/2]bbab49lf:49,rf:58,rs:8,a:1
[4/3]abab37lf:22,lp:15,rf:22,rp:15,rs:8,re:1,lprp:14,lprs:7
[4/4]bbaa32lf:16,ls:16
[4/5]baba15lf:15,rf:13,a:1
[4/6]aabb9lf:9,rf:7
[5/0]babba56lf:56,rf:51,a:1
[5/1]abbab49lf:49,rf:58,rs:8,a:1
[5/2]bbabb36lf:36,rf:38,a:3
[5/3]ababb33lf:20,lp:13,rf:13,rp:13,lprp:12,a:1
[5/4]abbaa32lf:16,ls:16
[5/5]bbaba13lf:13,rf:12,a:1
[5/6]aabba9lf:9,rf:7
[6/0]babbab49lf:49,rf:51,rs:8,a:2
[6/1]bbabba36lf:36,rf:38,a:3
[6/2]abbabb36lf:36,rf:38,a:3
[6/3]ababba33lf:20,lp:13,rf:13,rp:13,lprp:12,a:1
[6/4]aabbaa18lf:9,ls:9
[6/5]babbaa14lf:7,ls:7,a:1
[6/6]abbaba13lf:13,rf:12,a:1
[7/0]bbabbab36lf:36,rf:38,rs:7,a:3
[7/1]babbabb36lf:36,rf:38,a:3
[7/2]abbabba36lf:36,rf:38,a:3
[7/3]ababbab26lf:13,lp:13,rf:13,rp:13,rs:1,re:1,lprp:12,a:2
[7/4]baabbaa16lf:8,ls:8,a:2
[7/5]ababbaa14lf:7,ls:7,a:1
[7/6]babbaba13lf:13,rf:5,a:3

Considering [length 4 / frequency 0] abba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbaa=abab⟩.