| Back: | ⟨a, b | aaabaaa=abab⟩ |
|---|
Solved by morph:6/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaababab ⇒ ababbaaa |
| 2. | aaabaaa ⇒ abab |
| 3. | aaabaabab ⇒ abababaaa |
| 4. | ababaababab ⇒ ababbabbaaa |
| 5. | ababaabaaa ⇒ ababbab |
| 6. | ababaabaabab ⇒ ababbababaaa |
| 7. | ababbabaababab ⇒ ababbabbabbaaa |
| 8. | ababbabaabaaa ⇒ ababbabbab |
| 9. | ababbabbabaabaaa ⇒ ababbabbabbab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 46 | lf:35,lp:6,ls:5,rf:30,rp:9,rs:4,lprp:6,lsrp:5,lprs:3 |
|---|---|---|---|
| [2/1] | ba | 30 | lf:30,rf:26 |
| [2/2] | aa | 29 | lf:22,lp:3,ls:4,rf:10,rs:5,lprs:2 |
| [2/3] | bb | 4 | lf:4,rf:13,a:1 |
| [3/0] | aba | 32 | lf:26,lp:6,rf:13,rp:9,lprp:6 |
| [3/1] | bab | 23 | lf:18,ls:5,rf:21,rs:4 |
| [3/2] | aaa | 14 | lf:7,lp:3,ls:4,rf:5,rs:5,lprs:2 |
| [3/3] | baa | 12 | lf:12,rf:5 |
| [3/4] | aab | 11 | lf:11 |
| [3/5] | abb | 4 | lf:4,rf:13,a:1 |
| [3/6] | bba | 4 | lf:4,rf:13,a:1 |
| [4/0] | abab | 25 | lf:14,lp:6,ls:5,rf:11,rp:9,rs:1,re:1,lprp:6,lsrp:5 |
| [4/1] | abaa | 12 | lf:12,rf:2 |
| [4/2] | aaba | 11 | lf:11 |
| [4/3] | baba | 9 | lf:9,rf:4,a:1 |
| [4/4] | baaa | 8 | lf:4,ls:4,rf:5,rs:5 |
| [4/5] | baab | 8 | lf:8,a:2 |
| [4/6] | aaab | 6 | lf:3,lp:3 |
| [5/0] | ababa | 9 | lf:6,lp:3,rf:3,rp:1,a:1 |
| [5/1] | abaaa | 8 | lf:4,ls:4,rf:2,rs:2 |
| [5/2] | abaab | 8 | lf:8,a:2 |
| [5/3] | baaba | 8 | lf:8,a:2 |
| [5/4] | aabab | 7 | lf:5,ls:2,a:1 |
| [5/5] | aaaba | 6 | lf:3,lp:3 |
| [5/6] | aabaa | 6 | lf:6 |
| [6/0] | aabaaa | 8 | lf:4,ls:4 |
| [6/1] | abaaba | 8 | lf:8,a:2 |
| [6/2] | ababaa | 6 | lf:3,lp:3,rf:2,a:2 |
| [6/3] | ababab | 6 | lf:3,ls:3,rf:1,rp:1,a:1 |
| [6/4] | baabab | 6 | lf:4,ls:2,a:2 |
| [6/5] | babaab | 6 | lf:6,a:3 |
| [6/6] | ababba | 6 | lf:3,lp:3,rf:7,rp:7,lprp:3,a:1 |
| [7/0] | baabaaa | 6 | lf:3,ls:3,a:3 |
| [7/1] | aababab | 6 | lf:3,ls:3,a:1 |
| [7/2] | abaabab | 6 | lf:4,ls:2,a:2 |
| [7/3] | ababaab | 6 | lf:3,lp:3,a:3 |
| [7/4] | babaaba | 6 | lf:6,a:3 |
| [7/5] | ababbab | 6 | lf:3,lp:3,rf:6,rp:6,rs:1,re:1,lprp:3,a:3 |
| [7/6] | abaabaa | 4 | lf:4,a:3 |
Considering [length 6 / frequency 0] aabaaa=c.
Rewriting system is complete. See ⟨a, b | aaabaaa=abab⟩.