Morphocompletion for #4881 ⟨a, b | abbbaaab=aba⟩

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abbbaaab ⇒ aba
2. ababbaaab ⇒ abaa
3. abaabbaaab ⇒ abaaa
4. abaaabbaaab ⇒ abaaaa
5. abaaaabbaaab ⇒ abaaaaa
6. abaaaaabbaaab ⇒ abaaaaaa
7. abaaaaaabbaaab ⇒ abaaaaaaa
8. abaaaaaaabbaaab ⇒ abaaaaaaaa
9. abaaaaaaaabbaaab ⇒ abaaaaaaaaa
10. abaaaaaaaaabbaaab ⇒ abaaaaaaaaaa
11. abaaaaaaaaaabbaaab ⇒ abaaaaaaaaaaa
12. abaaaaaaaaaaabbaaab ⇒ abaaaaaaaaaaaa
13. abaaaaaaaaaaaabbaaab ⇒ abaaaaaaaaaaaaa
14. abaaaaaaaaaaaaabbaaab ⇒ abaaaaaaaaaaaaaa
15. abaaaaaaaaaaaaaabbaaab ⇒ abaaaaaaaaaaaaaaa
16. abaaaaaaaaaaaaaaabbaaab ⇒ abaaaaaaaaaaaaaaaa
17. abaaaaaaaaaaaaaaaabbaaab ⇒ abaaaaaaaaaaaaaaaaa
18. abaaaaaaaaaaaaaaaaabbaaab ⇒ abaaaaaaaaaaaaaaaaaa
19. abaaaaaaaaaaaaaaaaaabbaaab ⇒ abaaaaaaaaaaaaaaaaaaa
20. abaaaaaaaaaaaaaaaaaaabbaaab ⇒ abaaaaaaaaaaaaaaaaaaaa
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa211lf:211,rf:190,rs:19
[2/1]ab99lf:59,lp:20,ls:20,rf:20,rp:20,lprp:20,lsrp:20
[2/2]ba39lf:39,rf:20,rs:1
[2/3]bb21lf:21
[3/0]aaa173lf:173,rf:171,rs:18
[3/1]aab58lf:38,ls:20
[3/2]aba38lf:19,lp:19,rf:20,rp:20,rs:1,re:1,lprp:19
[3/3]baa38lf:38,rf:19,rs:1
[3/4]abb21lf:20,lp:1
[3/5]bba20lf:20
[3/6]bab1lf:1,a:1
[4/0]aaaa136lf:136,rf:153,rs:17,a:3
[4/1]aaab57lf:37,ls:20
[4/2]baaa37lf:37,rf:18,rs:1
[4/3]abaa36lf:18,lp:18,rf:19,rp:19,rs:1,re:1,lprp:18,a:1
[4/4]bbaa20lf:20
[4/5]abba19lf:19,a:1
[4/6]aabb18lf:18,a:2
[5/0]aaaaa120lf:120,rf:136,rs:16,a:4
[5/1]baaab41lf:21,ls:20
[5/2]abaaa34lf:17,lp:17,rf:18,rp:18,rs:1,re:1,lprp:17,a:2
[5/3]bbaaa20lf:20
[5/4]abbaa19lf:19,a:1
[5/5]aabba18lf:18,a:2
[5/6]aaabb17lf:17,a:3
[6/0]aaaaaa105lf:105,rf:120,rs:15,a:5
[6/1]bbaaab40lf:20,ls:20
[6/2]abaaaa32lf:16,lp:16,rf:17,rp:17,rs:1,re:1,lprp:16,a:3
[6/3]abbaaa19lf:19,a:1
[6/4]aabbaa18lf:18,a:2
[6/5]aaabba17lf:17,a:3
[6/6]aaaabb16lf:16,a:4
[7/0]aaaaaaa91lf:91,rf:105,rs:14,a:6
[7/1]abbaaab38lf:19,ls:19,a:1
[7/2]abaaaaa30lf:15,lp:15,rf:16,rp:16,rs:1,re:1,lprp:15,a:4
[7/3]aabbaaa18lf:18,a:2
[7/4]aaabbaa17lf:17,a:3
[7/5]aaaabba16lf:16,a:4
[7/6]aaaaabb15lf:15,a:5

Considering [length 3 / frequency 1] aab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbbaaab=aba⟩.