Morphocompletion for #4858 ⟨a, b | abbaaaab=bab

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abbaaaab ⇒ bab
2. abbaaabab ⇒ bbab
3. abbaaabbab ⇒ bbbab
4. abbaaabbbab ⇒ bbbbab
5. abbaaabbbbab ⇒ bbbbbab
6. abbaaabbbbbab ⇒ bbbbbbab
7. abbaaabbbbbbab ⇒ bbbbbbbab
8. abbaaabbbbbbbab ⇒ bbbbbbbbab
9. abbaaabbbbbbbbab ⇒ bbbbbbbbbab
10. abbaaabbbbbbbbbab ⇒ bbbbbbbbbbab
11. abbaaabbbbbbbbbbab ⇒ bbbbbbbbbbbab
12. abbaaabbbbbbbbbbbab ⇒ bbbbbbbbbbbbab
13. abbaaabbbbbbbbbbbbab ⇒ bbbbbbbbbbbbbab
14. abbaaabbbbbbbbbbbbbab ⇒ bbbbbbbbbbbbbbab
15. abbaaabbbbbbbbbbbbbbab ⇒ bbbbbbbbbbbbbbbab
16. abbaaabbbbbbbbbbbbbbbab ⇒ bbbbbbbbbbbbbbbbab
17. abbaaabbbbbbbbbbbbbbbbab ⇒ bbbbbbbbbbbbbbbbbab
18. abbaaabbbbbbbbbbbbbbbbbab ⇒ bbbbbbbbbbbbbbbbbbab
19. abbaaabbbbbbbbbbbbbbbbbbab ⇒ bbbbbbbbbbbbbbbbbbbab
20. abbaaabbbbbbbbbbbbbbbbbbbab ⇒ bbbbbbbbbbbbbbbbbbbbab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:[3/0] bbb, [3/1] abb, [3/2] bab, [3/3] bba, [3/4] aab, [3/5] aaa, [3/6] baa
Length 4:[4/0] bbbb, [4/1] abba, [4/2] bbab, [4/3] aaab, [4/4] bbaa, [4/5] baaa, [4/6] aabb
Length 5:[5/0] bbbbb, [5/1] abbaa, [5/2] bbbab, [5/3] bbaaa, [5/4] baaab, [5/5] aaabb, [5/6] aabbb
Length 6:[6/0] bbbbbb, [6/1] abbaaa, [6/2] bbbbab, [6/3] bbaaab, [6/4] baaabb, [6/5] aaabbb, [6/6] aabbbb
Length 7:[7/0] bbbbbbb, [7/1] abbaaab, [7/2] bbbbbab, [7/3] bbaaabb, [7/4] baaabbb, [7/5] aaabbbb, [7/6] aabbbbb

Considering [length 2 / frequency 1] ab=c.

Step 2

Rewriting system is complete. See a, b | abbaaaab=bab.