Morphocompletion for #4855 ⟨a, b | abbaaaab=aba⟩

Back:⟨a, b | abbaaaab=aba⟩

Solved by morph:5/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaaaab ⇒ aba
2. ababaaaab ⇒ abaa
3. abaabaaaab ⇒ abaaa
4. ababaaaaa ⇒ abaaaaaab
5. abaaabaaaab ⇒ abaaaa
6. abaabaaaaa ⇒ abaaaaaaab
7. abaaaabaaaab ⇒ abaaaaa
8. abaaabaaaaa ⇒ abaaaaaaaab
9. abaaaaabaaaab ⇒ abaaaaaa
10. abaaaaaabaaaab ⇒ abaaaaaaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aba, [3/2] aab, [3/3] baa, [3/4] bab, [3/5] abb, [3/6] bba
Length 4:[4/0] abaa, [4/1] aaaa, [4/2] aaab, [4/3] baaa, [4/4] aaba, [4/5] abab, [4/6] baba
Length 5:[5/0] abaaa, [5/1] aaaab, [5/2] baaaa, [5/3] aaaaa, [5/4] aabaa, [5/5] aaaba, [5/6] ababa
Length 6:[6/0] abaaaa, [6/1] baaaab, [6/2] baaaaa, [6/3] aabaaa, [6/4] aaabaa, [6/5] ababaa, [6/6] abaaba
Length 7:[7/0] abaaaab, [7/1] abaaaaa, [7/2] aabaaaa, [7/3] aaabaaa, [7/4] ababaaa, [7/5] abaabaa, [7/6] abaaaba

Considering [length 5 / frequency 2] baaaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbaaaab=aba⟩.