Morphocompletion for #4853 ⟨a, b | abbaaaab=aaa

Solved by morph:3/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abbaaaaaa ⇒ aaabaaaab
2. abbaaaab ⇒ aaa
3. aaaaaaabbbaaaaaa ⇒ aaaaaaabaabaaaab
4. aaaaaaabbbaaaab ⇒ aaaaaaabaa
5. aaaaaaababbbaaaab ⇒ aaaaaaababaa
6. aaabaaaabbbaaaab ⇒ aaabaaaabaa
7. aaabaaaababbbaaaab ⇒ aaabaaaababaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] bb, [2/3] ba
Length 3:[3/0] aaa, [3/1] aab, [3/2] abb, [3/3] baa, [3/4] bba, [3/5] bbb, [3/6] aba
Length 4:[4/0] aaaa, [4/1] aaab, [4/2] baaa, [4/3] bbaa, [4/4] bbba, [4/5] abbb, [4/6] abba
Length 5:[5/0] aaaaa, [5/1] aaaab, [5/2] baaaa, [5/3] bbaaa, [5/4] aaaba, [5/5] bbbaa, [5/6] abbba
Length 6:[6/0] aaaaaa, [6/1] baaaab, [6/2] bbaaaa, [6/3] bbbaaa, [6/4] abbbaa, [6/5] abbaaa, [6/6] aaabaa
Length 7:[7/0] bbaaaab, [7/1] aaaaaaa, [7/2] bbbaaaa, [7/3] abbbaaa, [7/4] abbaaaa, [7/5] baaaaaa, [7/6] aaabaaa

Considering [length 3 / frequency 2] abb=c.

Step 2

Rewriting system is complete. See a, b | abbaaaab=aaa.