| Back: | ⟨a, b | ababbaab=bab⟩ |
|---|
Solved by morph:3/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | ababbaab ⇒ bab |
| 2. | ababbabab ⇒ bbab |
| 3. | bbabbaab ⇒ ababbbab |
| 4. | ababbabbab ⇒ bbbab |
| 5. | bbabbabab ⇒ ababbbbab |
| 6. | abaababbbbab ⇒ bbbabab |
| 7. | ababbabbbab ⇒ bbbbab |
| 8. | bbabbabbab ⇒ ababbbbbab |
| 9. | abaababbbbbab ⇒ bbbabbab |
| 10. | ababbabbbbab ⇒ bbbbbab |
| 11. | ababbabbbbbab ⇒ bbbbbbab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 58 | lf:39,lp:8,ls:11,rf:19,rp:3,rs:11,lsrp:3,lprs:8,lsrs:11 |
|---|---|---|---|
| [2/1] | bb | 33 | lf:30,lp:3,rf:29,rp:7 |
| [2/2] | ba | 31 | lf:31,rf:16,rp:1 |
| [2/3] | aa | 4 | lf:4 |
| [3/0] | bab | 36 | lf:27,ls:9,rf:16,rp:1,rs:11,re:1,lsrs:9 |
| [3/1] | bba | 22 | lf:19,lp:3,rf:11,rp:1 |
| [3/2] | aba | 20 | lf:12,lp:8,rf:4,rp:3 |
| [3/3] | abb | 16 | lf:16,rf:4 |
| [3/4] | bbb | 11 | lf:11,rf:18,rp:6,a:2 |
| [3/5] | aab | 6 | lf:4,ls:2 |
| [3/6] | baa | 4 | lf:4 |
| [4/0] | bbab | 27 | lf:17,lp:3,ls:7,rf:11,rp:1,rs:9,re:1,lprs:3,lsrs:6,a:1 |
| [4/1] | abab | 18 | lf:10,lp:6,ls:2,rf:4,rp:3,rs:1,lsrp:1 |
| [4/2] | babb | 16 | lf:16,rf:4 |
| [4/3] | abba | 11 | lf:11,rf:1 |
| [4/4] | bbbb | 6 | lf:6,rf:9,rp:3,a:4 |
| [4/5] | baab | 6 | lf:4,ls:2 |
| [4/6] | bbba | 5 | lf:5,rf:9,rp:3,a:2 |
| [5/0] | ababb | 14 | lf:8,lp:6,rf:3,rp:3 |
| [5/1] | bbabb | 11 | lf:8,lp:3,rf:1,a:2 |
| [5/2] | babba | 11 | lf:11,rf:1 |
| [5/3] | abbab | 11 | lf:9,ls:2,rf:1,rs:1,a:1 |
| [5/4] | bbbab | 10 | lf:5,ls:5,rf:9,rp:3,rs:7,re:1,lsrp:2,lsrs:3,a:2 |
| [5/5] | babbb | 5 | lf:5,rf:3,a:3 |
| [5/6] | bbbba | 4 | lf:4,rf:5,rp:1,a:4 |
| [6/0] | ababba | 12 | lf:6,lp:6 |
| [6/1] | babbab | 11 | lf:9,ls:2,rf:1,rs:1,a:1 |
| [6/2] | bbbbab | 8 | lf:4,ls:4,rf:5,rp:1,rs:5,re:1,lsrs:2,a:4 |
| [6/3] | bbabba | 8 | lf:5,lp:3,rf:1,a:2 |
| [6/4] | abbabb | 5 | lf:5,a:2 |
| [6/5] | babbbb | 4 | lf:4,rf:2,a:4 |
| [6/6] | bbabab | 4 | lf:2,ls:2,rf:1,rs:1,a:1 |
| [7/0] | ababbab | 10 | lf:5,lp:5,a:1 |
| [7/1] | bbabbab | 8 | lf:4,lp:2,ls:2,rf:1,rs:1,a:2 |
| [7/2] | babbabb | 5 | lf:5,a:2 |
| [7/3] | bbbbbab | 4 | lf:2,ls:2,rf:3,rp:1,rs:3,re:1,lsrs:1,a:6 |
| [7/4] | abbbbab | 4 | lf:2,ls:2,rf:1,rs:1,a:4 |
| [7/5] | babbaab | 4 | lf:2,ls:2 |
| [7/6] | abbabab | 4 | lf:2,ls:2,a:1 |
Considering [length 3 / frequency 1] bba=c.
Rewriting system is complete. See ⟨a, b | ababbaab=bab⟩.