Morphocompletion for #4836 ⟨a, b | ababbaab=bab

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababbaab ⇒ bab
2. ababbabab ⇒ bbab
3. bbabbaab ⇒ ababbbab
4. ababbabbab ⇒ bbbab
5. bbabbabab ⇒ ababbbbab
6. abaababbbbab ⇒ bbbabab
7. ababbabbbab ⇒ bbbbab
8. bbabbabbab ⇒ ababbbbbab
9. abaababbbbbab ⇒ bbbabbab
10. ababbabbbbab ⇒ bbbbbab
11. bbabbabbbab ⇒ ababbbbbbab
12. ababbabbbbbab ⇒ bbbbbbab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] bb, [2/2] ba, [2/3] aa
Length 3:[3/0] bab, [3/1] bba, [3/2] aba, [3/3] abb, [3/4] bbb, [3/5] aab, [3/6] baa
Length 4:[4/0] bbab, [4/1] babb, [4/2] abab, [4/3] abba, [4/4] bbbb, [4/5] bbba, [4/6] abbb
Length 5:[5/0] bbabb, [5/1] ababb, [5/2] bbbab, [5/3] babba, [5/4] abbab, [5/5] babbb, [5/6] bbbba
Length 6:[6/0] babbab, [6/1] ababba, [6/2] bbabba, [6/3] bbbbab, [6/4] abbabb, [6/5] bbabbb, [6/6] babbbb
Length 7:[7/0] bbabbab, [7/1] ababbab, [7/2] babbabb, [7/3] bbbbbab, [7/4] babbbab, [7/5] abbbbab, [7/6] abbabbb

Considering [length 3 / frequency 1] bba=c.

Step 2

Rewriting system is complete. See a, b | ababbaab=bab.