Morphocompletion for #4835 ⟨a, b | ababbaab=baa

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. ababbaab ⇒ baa
2. baaabbaab ⇒ ababbabaa
3. ababbaaababbabaa ⇒ baaaaabbaab
4. baaaaabbaabbabbaab ⇒ ababbaaababbababaa
5. baaabbaaababbabaa ⇒ ababbabaaaaabbaab
6. ababbaaababbaaababbababaa ⇒ baaaaaaabbaabbabbaab
7. baaaaaaabbaabbabbaabbabbaab ⇒ ababbaaababbaaababbabababaa
8. baaaaabbaabbabbaaababbabaa ⇒ ababbaaababbababaaaaabbaab
9. baaabbaaababbaaababbababaa ⇒ ababbabaaaaaaabbaabbabbaab
10. ababbaaababbaaababbaaababbabababaa ⇒ baaaaaaaaabbaabbabbaabbabbaab
11. baaaaaaaaabbaabbabbaabbabbaabbabbaab ⇒ ababbaaababbaaababbaaababbababababaa
12. baaaaaaabbaabbabbaabbabbaaababbabaa ⇒ ababbaaababbaaababbabababaaaaabbaab
13. baaaaabbaabbabbaaababbaaababbababaa ⇒ ababbaaababbababaaaaaaabbaabbabbaab
14. baaabbaaababbaaababbaaababbabababaa ⇒ ababbabaaaaaaaaabbaabbabbaabbabbaab
15. ababbaaababbaaababbaaababbaaababbababababaa ⇒ baaaaaaaaaaabbaabbabbaabbabbaabbabbaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] aa, [2/2] ab, [2/3] bb
Length 3:[3/0] baa, [3/1] bba, [3/2] bab, [3/3] abb, [3/4] aaa, [3/5] aba, [3/6] aab
Length 4:[4/0] abba, [4/1] baaa, [4/2] abab, [4/3] bbaa, [4/4] babb, [4/5] aaab, [4/6] aaaa
Length 5:[5/0] abbaa, [5/1] babba, [5/2] ababb, [5/3] baaab, [5/4] aaaba, [5/5] bbaaa, [5/6] babaa
Length 6:[6/0] ababba, [6/1] babbaa, [6/2] baaaba, [6/3] abbaaa, [6/4] aaabab, [6/5] bbaaab, [6/6] abbaab
Length 7:[7/0] bbaaaba, [7/1] baaabab, [7/2] abbaaab, [7/3] ababbaa, [7/4] aababba, [7/5] aaababb, [7/6] babbaaa

Considering [length 2 / frequency 0] ba=c.

Step 2

Rewriting system is complete. See a, b | ababbaab=baa.