Morphocompletion for #4833 ⟨a, b | ababbaab=aba⟩

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ababbaab ⇒ aba
2. abaabbaab ⇒ abaa
3. abaaabbaab ⇒ abaaa
4. abaaaabbaab ⇒ abaaaa
5. abaaaaabbaab ⇒ abaaaaa
6. abaaaaaabbaab ⇒ abaaaaaa
7. abaaaaaaabbaab ⇒ abaaaaaaa
8. abaaaaaaaabbaab ⇒ abaaaaaaaa
9. abaaaaaaaaabbaab ⇒ abaaaaaaaaa
10. abaaaaaaaaaabbaab ⇒ abaaaaaaaaaa
11. abaaaaaaaaaaabbaab ⇒ abaaaaaaaaaaa
12. abaaaaaaaaaaaabbaab ⇒ abaaaaaaaaaaaa
13. abaaaaaaaaaaaaabbaab ⇒ abaaaaaaaaaaaaa
14. abaaaaaaaaaaaaaabbaab ⇒ abaaaaaaaaaaaaaa
15. abaaaaaaaaaaaaaaabbaab ⇒ abaaaaaaaaaaaaaaa
16. abaaaaaaaaaaaaaaaabbaab ⇒ abaaaaaaaaaaaaaaaa
17. abaaaaaaaaaaaaaaaaabbaab ⇒ abaaaaaaaaaaaaaaaaa
18. abaaaaaaaaaaaaaaaaaabbaab ⇒ abaaaaaaaaaaaaaaaaaa
19. abaaaaaaaaaaaaaaaaaaabbaab ⇒ abaaaaaaaaaaaaaaaaaaa
20. abaaaaaaaaaaaaaaaaaaaabbaab ⇒ abaaaaaaaaaaaaaaaaaaaa
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa210lf:210,rf:190,rs:19
[2/1]ab100lf:60,lp:20,ls:20,rf:20,rp:20,lprp:20,lsrp:20
[2/2]ba40lf:40,rf:20,rs:1
[2/3]bb20lf:20
[3/0]aaa171lf:171,rf:171,rs:18,a:2
[3/1]aab59lf:39,ls:20
[3/2]aba40lf:20,lp:20,rf:20,rp:20,rs:1,re:1,lprp:20,lprs:1
[3/3]baa39lf:39,rf:19,rs:1
[3/4]abb20lf:20
[3/5]bba20lf:20
[3/6]bab1lf:1
[4/0]aaaa153lf:153,rf:153,rs:17,a:3
[4/1]baab41lf:21,ls:20
[4/2]abaa38lf:19,lp:19,rf:19,rp:19,rs:1,re:1,lprp:19,lprs:1,a:1
[4/3]abba20lf:20
[4/4]bbaa20lf:20
[4/5]aabb19lf:19,a:1
[4/6]aaab18lf:18,a:2
[5/0]aaaaa136lf:136,rf:136,rs:16,a:4
[5/1]bbaab40lf:20,ls:20
[5/2]abaaa36lf:18,lp:18,rf:18,rp:18,rs:1,re:1,lprp:18,lprs:1,a:2
[5/3]abbaa20lf:20
[5/4]aabba19lf:19,a:1
[5/5]aaabb18lf:18,a:2
[5/6]aaaab17lf:17,a:3
[6/0]aaaaaa120lf:120,rf:120,rs:15,a:5
[6/1]abbaab40lf:20,ls:20
[6/2]abaaaa34lf:17,lp:17,rf:17,rp:17,rs:1,re:1,lprp:17,lprs:1,a:3
[6/3]aabbaa19lf:19,a:1
[6/4]aaabba18lf:18,a:2
[6/5]aaaabb17lf:17,a:3
[6/6]aaaaab16lf:16,a:4
[7/0]aaaaaaa105lf:105,rf:105,rs:14,a:6
[7/1]aabbaab38lf:19,ls:19,a:1
[7/2]abaaaaa32lf:16,lp:16,rf:16,rp:16,rs:1,re:1,lprp:16,lprs:1,a:4
[7/3]aaabbaa18lf:18,a:2
[7/4]aaaabba17lf:17,a:3
[7/5]aaaaabb16lf:16,a:4
[7/6]aaaaaab15lf:15,a:5

Considering [length 3 / frequency 1] aab=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababbaab=aba⟩.