Morphocompletion for #4832 ⟨a, b | ababbaab=aab⟩

Solved by morph:6/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ababbaab ⇒ aab
2. ababbaaab ⇒ aaab
3. ababbaaaab ⇒ aaaab
4. ababbaaaaab ⇒ aaaaab
5. ababbaaaaaab ⇒ aaaaaab
6. ababbaaaaaaab ⇒ aaaaaaab
7. ababbaaaaaaaab ⇒ aaaaaaaab
8. ababbaaaaaaaaab ⇒ aaaaaaaaab
9. ababbaaaaaaaaaab ⇒ aaaaaaaaaab
10. ababbaaaaaaaaaaab ⇒ aaaaaaaaaaab
11. ababbaaaaaaaaaaaab ⇒ aaaaaaaaaaaab
12. ababbaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaab
13. ababbaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaab
14. ababbaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaab
15. ababbaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaab
16. ababbaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaab
17. ababbaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaab
18. ababbaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaab
19. ababbaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaab
20. ababbaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa210lf:210,rf:210,rp:20
[2/1]ab100lf:60,lp:20,ls:20,rf:20,rs:20,lprs:20,lsrs:20
[2/2]ba40lf:40
[2/3]bb20lf:20
[3/0]aaa190lf:190,rf:190,rp:19,a:1
[3/1]aba40lf:20,lp:20
[3/2]aab40lf:20,ls:20,rf:20,rp:1,rs:20,re:1,lsrp:1,lsrs:20
[3/3]bba20lf:20
[3/4]bab20lf:20
[3/5]baa20lf:20
[3/6]abb20lf:20
[4/0]aaaa171lf:171,rf:171,rp:18,a:2
[4/1]abab40lf:20,lp:20
[4/2]aaab38lf:19,ls:19,rf:19,rp:1,rs:19,re:1,lsrp:1,lsrs:19,a:1
[4/3]bbaa20lf:20
[4/4]babb20lf:20
[4/5]abba20lf:20
[4/6]baaa19lf:19,a:1
[5/0]aaaaa153lf:153,rf:153,rp:17,a:3
[5/1]ababb40lf:20,lp:20
[5/2]aaaab36lf:18,ls:18,rf:18,rp:1,rs:18,re:1,lsrp:1,lsrs:18,a:2
[5/3]babba20lf:20
[5/4]abbaa20lf:20
[5/5]bbaaa19lf:19,a:1
[5/6]baaaa18lf:18,a:2
[6/0]aaaaaa136lf:136,rf:136,rp:16,a:4
[6/1]ababba40lf:20,lp:20
[6/2]aaaaab34lf:17,ls:17,rf:17,rp:1,rs:17,re:1,lsrp:1,lsrs:17,a:3
[6/3]babbaa20lf:20
[6/4]abbaaa19lf:19,a:1
[6/5]bbaaaa18lf:18,a:2
[6/6]baaaaa17lf:17,a:3
[7/0]aaaaaaa120lf:120,rf:120,rp:15,a:5
[7/1]ababbaa40lf:20,lp:20
[7/2]aaaaaab32lf:16,ls:16,rf:16,rp:1,rs:16,re:1,lsrp:1,lsrs:16,a:4
[7/3]babbaaa19lf:19,a:1
[7/4]abbaaaa18lf:18,a:2
[7/5]bbaaaaa17lf:17,a:3
[7/6]baaaaaa16lf:16,a:4

Considering [length 6 / frequency 1] ababba=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababbaab=aab⟩.