Morphocompletion for #4828 ⟨a, b | abababba=bab

Solved by morph:6/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abababba ⇒ bab
2. babbababba ⇒ abababbbab
3. abaabababbbab ⇒ babbabba
4. babbabbaababba ⇒ abaabababbbbab
5. abaabaabababbbbab ⇒ babbbaababba
6. ababababababbbab ⇒ babbbababba
7. abababbbabbabba ⇒ babbaabababbbab
8. babbbababbaababba ⇒ ababababababbbbab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] bb, [2/3] aa
Length 3:[3/0] bab, [3/1] aba, [3/2] bba, [3/3] abb, [3/4] bbb, [3/5] baa, [3/6] aab
Length 4:[4/0] abab, [4/1] babb, [4/2] abba, [4/3] bbab, [4/4] baba, [4/5] bbba, [4/6] abbb
Length 5:[5/0] babba, [5/1] ababa, [5/2] babab, [5/3] ababb, [5/4] bbbab, [5/5] babbb, [5/6] baaba
Length 6:[6/0] ababab, [6/1] ababba, [6/2] bababb, [6/3] abbbab, [6/4] babbba, [6/5] babbab, [6/6] abaaba
Length 7:[7/0] babbbab, [7/1] abababb, [7/2] bababba, [7/3] bababbb, [7/4] abababa, [7/5] aababba, [7/6] babbabb

Considering [length 6 / frequency 1] ababba=c.

Step 2

Rewriting system is complete. See a, b | abababba=bab.