| Back: | ⟨a, b | abababba=baa⟩ |
|---|
Solved by morph:2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: arenaTotalLimit
| # | Rule |
|---|---|
| 1. | abababba ⇒ baa |
| 2. | abababbbaa ⇒ babaa |
| 3. | abababbbabaa ⇒ bababaa |
| 4. | abababbbababaa ⇒ babababaa |
| 5. | abababbbabababaa ⇒ bababababaa |
| 6. | abababbbababababaa ⇒ babababababaa |
| 7. | abababbbabababababaa ⇒ bababababababaa |
| 8. | abababbbababababababaa ⇒ babababababababaa |
| 9. | abababbbabababababababaa ⇒ bababababababababaa |
| 10. | abababbbababababababababaa ⇒ babababababababababaa |
| 11. | abababbbabababababababababaa ⇒ bababababababababababaa |
| 12. | abababbbababababababababababaa ⇒ babababababababababababaa |
| 13. | abababbbabababababababababababaa ⇒ bababababababababababababaa |
| 14. | abababbbababababababababababababaa ⇒ babababababababababababababaa |
| 15. | abababbbabababababababababababababaa ⇒ bababababababababababababababaa |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa |
|---|---|
| Length 3: | [3/0] aba, [3/1] bab, [3/2] baa, [3/3] bba, [3/4] abb, [3/5] bbb |
| Length 4: | [4/0] abab, [4/1] baba, [4/2] abaa, [4/3] babb, [4/4] bbba, [4/5] abbb, [4/6] bbab |
| Length 5: | [5/0] ababa, [5/1] babab, [5/2] babaa, [5/3] ababb, [5/4] abbba, [5/5] babbb, [5/6] bbaba |
| Length 6: | [6/0] ababab, [6/1] bababa, [6/2] ababaa, [6/3] bababb, [6/4] babbba, [6/5] ababbb, [6/6] bbbaba |
| Length 7: | [7/0] abababa, [7/1] bababab, [7/2] abababb, [7/3] bababaa, [7/4] ababbba, [7/5] bababbb, [7/6] abbbaba |
Considering [length 2 / frequency 0] ab=c.
Rewriting system is complete. See ⟨a, b | abababba=baa⟩.