| Back: | ⟨a, b | abababab=baa⟩ |
|---|
Solved by morph:2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | baaab ⇒ abbaa |
| 2. | abababab ⇒ baa |
| 3. | baaaabbaa ⇒ abbaaaaab |
| 4. | abababaabbaa ⇒ baaaaab |
| 5. | baaaababbaa ⇒ abbaaaaabab |
| 6. | abababaababbaa ⇒ baaaaabab |
| 7. | baaaaabbababab ⇒ abababaabbabaa |
| 8. | baaaabababbaa ⇒ abbaaaaababab |
| 9. | abababaabababbaa ⇒ baaaaababab |
| 10. | baaaaababbababab ⇒ abababaababbabaa |
| 11. | baaaaabababbababab ⇒ abababaabababbabaa |
| 12. | baaaaabbababaabbaa ⇒ abababaabbabaaaaab |
| 13. | baaaabababaabbabaa ⇒ abbaaaaaaabbababab |
| 14. | abababaabababaabbabaa ⇒ baaaaaaabbababab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ba | 71 | lf:62,lp:9,rf:45,rp:5 |
|---|---|---|---|
| [2/1] | ab | 68 | lf:58,lp:5,ls:5,rf:49,rp:9,rs:9,lsrp:4,lprs:4 |
| [2/2] | aa | 55 | lf:46,ls:9,rf:49,rs:5 |
| [2/3] | bb | 13 | lf:13,rf:11,a:1 |
| [3/0] | aba | 45 | lf:40,lp:5,rf:29,rp:4 |
| [3/1] | baa | 43 | lf:25,lp:9,ls:9,rf:18,rp:5,rs:5,re:1,lsrp:4,lprs:4 |
| [3/2] | bab | 41 | lf:37,ls:4,rf:27,rs:6 |
| [3/3] | aaa | 21 | lf:21,rf:31,a:1 |
| [3/4] | aab | 17 | lf:16,ls:1,rf:13,rs:3,a:1 |
| [3/5] | bba | 13 | lf:13,rf:11,a:1 |
| [3/6] | abb | 13 | lf:13,rf:11,rp:5,a:1 |
| [4/0] | abab | 40 | lf:31,lp:5,ls:4,rf:21,rp:4,rs:6,lsrp:3,lprs:3 |
| [4/1] | baba | 27 | lf:27,rf:19 |
| [4/2] | baaa | 18 | lf:9,lp:9,rf:9,rp:4,a:1 |
| [4/3] | bbaa | 14 | lf:7,ls:7,rf:5,rs:1,a:1 |
| [4/4] | abba | 13 | lf:13,rf:11,rp:5,a:1 |
| [4/5] | aaaa | 12 | lf:12,rf:22,a:2 |
| [4/6] | abaa | 11 | lf:9,ls:2,rf:8,rs:3,a:2 |
| [5/0] | ababa | 26 | lf:21,lp:5,rf:13,rp:4 |
| [5/1] | babab | 22 | lf:18,ls:4,rf:11,rs:4 |
| [5/2] | baaaa | 16 | lf:8,lp:8,rf:9,rp:4,a:2 |
| [5/3] | abbaa | 14 | lf:7,ls:7,rf:5,rp:5,rs:1,re:1,lsrp:3,a:1 |
| [5/4] | babaa | 11 | lf:9,ls:2,rf:8,rs:3,a:2 |
| [5/5] | aaaab | 8 | lf:8,rf:9,rs:3,a:2 |
| [5/6] | aabab | 8 | lf:8,rf:6,rs:2,a:5 |
| [6/0] | ababab | 23 | lf:14,lp:5,ls:4,rf:9,rp:4,rs:4,lsrp:3,lprs:2 |
| [6/1] | bababa | 11 | lf:11,rf:6 |
| [6/2] | baaaaa | 8 | lf:4,lp:4,rf:9,rp:4,a:2 |
| [6/3] | baaaab | 8 | lf:4,lp:4,a:3 |
| [6/4] | babbaa | 8 | lf:4,ls:4,a:5 |
| [6/5] | ababaa | 7 | lf:7,rf:4,a:2 |
| [6/6] | babaab | 7 | lf:7,rf:4,a:2 |
| [7/0] | abababa | 12 | lf:7,lp:5,rf:4,rp:4 |
| [7/1] | baaaaab | 8 | lf:4,lp:4,rf:7,rp:3,rs:3,re:1,lprs:1,a:2 |
| [7/2] | ababbaa | 8 | lf:4,ls:4,a:5 |
| [7/3] | bababab | 8 | lf:4,ls:4,rf:2,rs:2 |
| [7/4] | bababaa | 7 | lf:7,rf:4,a:2 |
| [7/5] | ababaab | 7 | lf:7,rf:4,a:2 |
| [7/6] | baaaaba | 6 | lf:3,lp:3,a:5 |
Considering [length 2 / frequency 0] ba=c.
Rewriting system is complete. See ⟨a, b | abababab=baa⟩.