Morphocompletion for #4817 ⟨a, b | ababaaab=bba

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. ababaaab ⇒ bba
2. ababaabba ⇒ bbaabaaab
3. bbaabaaabbabaaab ⇒ ababaabbbba
4. ababaaaababaabbbba ⇒ bbabaabaaabbabaaab
5. bbaabaaabbabaabba ⇒ ababaabbbbaabaaab
6. bbabaabaaabbabaaabbabaaab ⇒ ababaaaababaabbbbbba
7. ababaaaababaaaababaabbbbbba ⇒ bbababaabaaabbabaaabbabaaab
8. bbaabaaabbabaaaababaabbbba ⇒ ababaabbbbabaabaaabbabaaab
9. bbabaabaaabbabaaabbabaabba ⇒ ababaaaababaabbbbbbaabaaab
10. bbababaabaaabbabaaabbabaaabbabaaab ⇒ ababaaaababaaaababaabbbbbbbba
11. ababaaaababaaaababaaaababaabbbbbbbba ⇒ bbabababaabaaabbabaaabbabaaabbabaaab
12. bbaabaaabbabaaaababaaaababaabbbbbba ⇒ ababaabbbbababaabaaabbabaaabbabaaab
13. bbabaabaaabbabaaabbabaaaababaabbbba ⇒ ababaaaababaabbbbbbabaabaaabbabaaab
14. bbababaabaaabbabaaabbabaaabbabaabba ⇒ ababaaaababaaaababaabbbbbbbbaabaaab
15. bbabababaabaaabbabaaabbabaaabbabaaabbabaaab ⇒ ababaaaababaaaababaaaababaabbbbbbbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bba, [3/2] aab, [3/3] baa, [3/4] bab, [3/5] aaa, [3/6] abb
Length 4:[4/0] abaa, [4/1] baba, [4/2] aaab, [4/3] baaa, [4/4] bbab, [4/5] aabb, [4/6] abba
Length 5:[5/0] babaa, [5/1] abaaa, [5/2] bbaba, [5/3] baaab, [5/4] aabba, [5/5] ababa, [5/6] abbab
Length 6:[6/0] abaaab, [6/1] bbabaa, [6/2] babaaa, [6/3] ababaa, [6/4] abbaba, [6/5] aabbab, [6/6] baaabb
Length 7:[7/0] abbabaa, [7/1] aabbaba, [7/2] baaabba, [7/3] babaaab, [7/4] aaabbab, [7/5] abaaabb, [7/6] bbabaaa

Considering [length 2 / frequency 0] ba=c.

Step 2

Rewriting system is complete. See a, b | ababaaab=bba.