Morphocompletion for #4816 ⟨a, b | ababaaab=bab⟩

Solved by morph:2/0,3/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababaaab ⇒ bab
2. abababab ⇒ bbabaaab
3. ababaabab ⇒ bbab
4. bbabaaabaaab ⇒ ababbab
5. abbbabaaab ⇒ bbabaaabab
6. abababbab ⇒ bbabaabab
7. ababaabbab ⇒ bbbab
8. bbabaaabaabab ⇒ ababbbab
9. abababbbab ⇒ bbabaabbab
10. ababaabbbab ⇒ bbbbab
11. ababaabbbbab ⇒ bbbbbab
...

Collecting factors up to length 7 / frequency 4:

[2/0]ab61lf:41,lp:9,ls:11,rf:22,rp:2,rs:11,lsrp:2,lprs:9,lsrs:11
[2/1]ba32lf:32,rf:20,rp:1
[2/2]bb15lf:13,lp:2,rf:18,rp:8,a:1
[2/3]aa15lf:15,rf:6
[3/0]aba32lf:24,lp:8,rf:8,rp:2
[3/1]bab30lf:22,ls:8,rf:16,rp:1,rs:10,re:1,lsrs:7
[3/2]aab13lf:10,ls:3,rf:4,rs:1
[3/3]bba10lf:8,lp:2,rf:11,rp:5,a:1
[4/0]abab25lf:14,lp:8,ls:3,rf:4,rp:2,rs:2,lsrp:1,lprs:1
[4/1]bbab15lf:8,lp:2,ls:5,rf:11,rp:5,rs:7,re:1,lsrp:2,lprs:2,lsrs:4,a:1
[4/2]baba12lf:12,rf:4
[4/3]abaa10lf:10,rf:4
[5/0]ababa17lf:9,lp:8
[5/1]baaab8lf:5,ls:3,rf:2,rs:1
[5/2]babaa8lf:8,rf:4
[5/3]bbbab7lf:4,ls:3,rf:4,rp:1,rs:4,re:1,lsrs:2,a:2
[6/0]ababaa10lf:5,lp:5
[6/1]ababab8lf:4,lp:3,ls:1,a:3
[6/2]abaaab8lf:5,ls:3,rf:2,rs:1
[6/3]abbbab6lf:3,lp:1,ls:2,rf:1,rs:1,a:5

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. accacc ⇒ cccaac
2. accaac ⇒ cc
3. cccaacaac ⇒ acccc
4. acccccaac ⇒ cccaacacc
5. accacacccc ⇒ cccaaacccc
6. accaaacccc ⇒ cacccc
7. accacacacccc ⇒ cccaaacacccc
8. accaaacacccc ⇒ cacacccc
9. cccaacacccaac ⇒ acccccacc
10. cccaacaaacccc ⇒ acccacccc
11. acccccacccaac ⇒ cccaacacccacc
12. acccccaaacccc ⇒ cccaacacacccc
13. accaaacccacccc ⇒ cacccacccc
14. accaaacacacccc ⇒ cacacacccc
15. bc ⇒ ccaac
16. bacccc ⇒ ccaaacccc
17. bacacccc ⇒ ccaaacacccc
18. bacccacccc ⇒ ccaaacccacccc
19. bacacacccc ⇒ ccaaacacacccc
20. ab ⇒ c
...

Collecting factors up to length 6 / frequency 7:

[2/0]cc87lf:71,lp:3,ls:13,rf:72,rp:12,rs:17,re:1,lsrp:8,lprs:3,lsrs:12,a:2
[2/1]ac61lf:45,lp:11,ls:5,rf:34,rp:3,rs:2,lsrp:2,lprs:1,a:2
[2/2]ca30lf:30,rf:31,rp:4,a:2
[2/3]aa20lf:20,rf:17,a:2
[2/4]ba8lf:4,lp:4,a:7
[3/0]ccc55lf:40,lp:3,ls:12,rf:39,rp:6,rs:13,lsrp:3,lprs:2,lsrs:12,a:4
[3/1]acc40lf:28,lp:11,ls:1,rf:21,rp:3,rs:3,lprs:2,a:3
[3/2]aac19lf:14,ls:5,rf:11,rs:2,a:2
[3/3]cca18lf:18,rf:16,rp:5,a:2
[3/4]cac16lf:16,rf:20,rp:4,a:4
[3/5]caa14lf:14,rf:11,a:2
[3/6]aca12lf:12,rf:11,a:5
[4/0]cccc30lf:18,ls:12,rf:15,rs:13,lsrs:12,a:5
[4/1]accc22lf:19,lp:3,rf:18,rp:3,a:5
[4/2]acca16lf:8,lp:8,a:3
[4/3]caac13lf:8,ls:5,rf:5,rs:2,a:2
[4/4]ccca13lf:10,lp:3,rf:11,rp:6,a:4
[4/5]cacc12lf:11,ls:1,rf:15,rp:2,rs:3,a:4
[4/6]ccaa12lf:12,rf:11,rp:5,a:2
[5/0]acccc30lf:15,lp:3,ls:12,rf:14,rp:2,rs:13,re:1,lprs:1,lsrs:12,a:5
[5/1]ccaac11lf:7,ls:4,rf:5,rp:1,rs:2,re:1,a:2
[5/2]accaa10lf:5,lp:5,a:3
[5/3]caccc10lf:10,rf:12,rp:2,a:8
[5/4]cccaa10lf:7,lp:3,rf:6,rp:6,a:4
[5/5]acacc7lf:7,rf:8,rs:1,a:6
[5/6]accac6lf:3,lp:3,a:4

Considering [length 3 / frequency 2] aac=d.

Step 3

Rewriting system is complete. See ⟨a, b | ababaaab=bab⟩.