Morphocompletion for #4812 ⟨a, b | ababaaab=aab⟩

Solved by morph:6/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ababaaab ⇒ aab
2. ababaaaab ⇒ aaab
3. ababaaaaab ⇒ aaaab
4. ababaaaaaab ⇒ aaaaab
5. ababaaaaaaab ⇒ aaaaaab
6. ababaaaaaaaab ⇒ aaaaaaab
7. ababaaaaaaaaab ⇒ aaaaaaaab
8. ababaaaaaaaaaab ⇒ aaaaaaaaab
9. ababaaaaaaaaaaab ⇒ aaaaaaaaaab
10. ababaaaaaaaaaaaab ⇒ aaaaaaaaaaab
11. ababaaaaaaaaaaaaab ⇒ aaaaaaaaaaaab
12. ababaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaab
13. ababaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaab
14. ababaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaab
15. ababaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaab
16. ababaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaab
17. ababaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaab
18. ababaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaab
19. ababaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaab
20. ababaaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa230lf:230,rf:210,rp:20
[2/1]ab100lf:60,lp:20,ls:20,rf:20,rs:20,lprs:20,lsrs:20
[2/2]ba40lf:40
[3/0]aaa210lf:210,rf:190,rp:19
[3/1]aba60lf:40,lp:20
[3/2]aab40lf:20,ls:20,rf:20,rp:1,rs:20,re:1,lsrp:1,lsrs:20
[3/3]bab20lf:20
[3/4]baa20lf:20
[4/0]aaaa190lf:190,rf:171,rp:18,a:1
[4/1]abab40lf:20,lp:20
[4/2]aaab40lf:20,ls:20,rf:19,rp:1,rs:19,re:1,lsrp:1,lsrs:19
[4/3]baba20lf:20
[4/4]baaa20lf:20
[4/5]abaa20lf:20
[5/0]aaaaa171lf:171,rf:153,rp:17,a:2
[5/1]ababa40lf:20,lp:20
[5/2]aaaab38lf:19,ls:19,rf:18,rp:1,rs:18,re:1,lsrp:1,lsrs:18,a:1
[5/3]babaa20lf:20
[5/4]abaaa20lf:20
[5/5]baaaa19lf:19,a:1
[5/6]baaab2lf:1,ls:1
[6/0]aaaaaa153lf:153,rf:136,rp:16,a:3
[6/1]ababaa40lf:20,lp:20
[6/2]aaaaab36lf:18,ls:18,rf:17,rp:1,rs:17,re:1,lsrp:1,lsrs:17,a:2
[6/3]babaaa20lf:20
[6/4]abaaaa19lf:19,a:1
[6/5]baaaaa18lf:18,a:2
[6/6]baaaab2lf:1,ls:1,a:1
[7/0]aaaaaaa136lf:136,rf:120,rp:15,a:4
[7/1]ababaaa40lf:20,lp:20
[7/2]aaaaaab34lf:17,ls:17,rf:16,rp:1,rs:16,re:1,lsrp:1,lsrs:16,a:3
[7/3]babaaaa19lf:19,a:1
[7/4]abaaaaa18lf:18,a:2
[7/5]baaaaaa17lf:17,a:3
[7/6]babaaab2lf:1,ls:1

Considering [length 6 / frequency 1] ababaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababaaab=aab⟩.