Morphocompletion for #4807 ⟨a, b | abaabbba=baa⟩

Solved by morph:6/1,3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaabbba ⇒ baa
2. abaabbbbaa ⇒ babaa
3. abaabbbbbaa ⇒ babbaa
4. abaabbbbabaa ⇒ bababaa
5. abaabbbbbbaa ⇒ babbbaa
6. abaabbbbabbaa ⇒ bababbaa
7. abaabbbbbabaa ⇒ babbabaa
8. abaabbbbababaa ⇒ babababaa
...

Collecting factors up to length 7 / frequency 4:

[2/0]ab29lf:21,lp:8,rf:12
[2/1]bb28lf:28,rf:5
[2/2]ba22lf:21,ls:1,rf:20,rp:8,lsrp:1
[2/3]aa22lf:15,ls:7,rf:8,rs:8,lsrs:7
[3/0]baa22lf:15,ls:7,rf:8,rp:1,rs:8,re:1,lsrs:7
[3/1]aba20lf:12,lp:8,rf:8
[3/2]bbb19lf:19,rf:1
[3/3]bba10lf:9,ls:1,rf:4
[4/0]abaa22lf:11,lp:8,ls:3,rf:4,rs:4,lprs:4,lsrs:3
[4/1]bbbb11lf:11,a:1
[4/2]bbba9lf:8,ls:1,rf:1
[4/3]abbb8lf:8,rf:1
[5/0]abaab16lf:8,lp:8
[5/1]baabb8lf:8
[5/2]aabbb8lf:8
[5/3]bbbba7lf:7,a:1
[6/0]abaabb16lf:8,lp:8
[6/1]baabbb8lf:8
[6/2]aabbbb7lf:7,a:1
[6/3]bbbbaa6lf:3,ls:3,a:1

Considering [length 6 / frequency 1] baabbb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. acaaccca ⇒ caa
2. acaacccc ⇒ cac
3. acaacccbc ⇒ cabc
4. baa ⇒ aca
5. bac ⇒ acc
6. bcaa ⇒ accaaccca
7. bcac ⇒ accaacccc
8. acaacccbbc ⇒ cabbc
9. babc ⇒ acbc
10. bcabc ⇒ accaacccbc
11. caabbb ⇒ acabbc
12. acabbb ⇒ c
13. accabbb ⇒ bc
14. acccabbb ⇒ bbc
15. accaaccccabbb ⇒ bcc
16. acccaaccccabbb ⇒ bbcc
17. accaacccccabbb ⇒ bcbc
18. bbbc ⇒ accccabbb
19. babbc ⇒ acbbc
20. bcabbc ⇒ accaacccbbc
...

Collecting factors up to length 6 / frequency 7:

[2/0]ac31lf:19,lp:10,ls:2,rf:15,rp:10,rs:1,lsrp:11,lprs:1,a:2
[2/1]bb27lf:19,lp:1,ls:7,rf:8,rp:2,rs:1,lsrp:2,lprs:1,a:3
[2/2]cc27lf:26,ls:1,rf:19,rs:4,a:4
[2/3]bc22lf:11,lp:4,ls:7,rf:13,rp:3,rs:10,re:1,lprs:2,lsrs:6,a:7
[2/4]ca21lf:19,lp:1,ls:1,rf:12,rp:4,rs:2,lsrp:1,a:2
[2/5]aa12lf:10,ls:2,rf:5,rs:1,a:2
[2/6]ab11lf:11,rf:4,a:3
[3/0]acc17lf:12,lp:5,rf:10,rp:6,rs:1,re:1,a:4
[3/1]bbb16lf:8,lp:1,ls:7,rf:1,rs:1,lprs:1,a:3
[3/2]ccc15lf:14,ls:1,rf:7,rs:1,a:5
[3/3]caa11lf:9,lp:1,ls:1,rf:5,rp:1,rs:1,re:1,a:5
[3/4]cca10lf:9,ls:1,rf:6,rs:1,a:5
[3/5]aca10lf:5,lp:5,rf:2,rp:2,rs:1,re:1,a:2
[3/6]abb9lf:9,rf:3,a:3
[4/0]abbb14lf:7,ls:7,rf:1,rs:1,a:3
[4/1]accc11lf:9,lp:2,rf:5,rp:1,a:5
[4/2]acaa8lf:4,lp:4,a:5
[4/3]cabb7lf:7,rf:3,rp:1,a:3
[4/4]aacc7lf:7,rf:4,a:5
[4/5]caac7lf:7,rf:4,a:5
[4/6]ccca7lf:6,ls:1,rf:2,rs:1,a:5
[5/0]cabbb12lf:6,ls:6,rf:1,rs:1,a:3
[5/1]acaac8lf:4,lp:4,a:5
[5/2]aaccc7lf:7,rf:4,a:5
[5/3]caacc7lf:7,rf:4,a:5
[5/4]accca6lf:3,lp:2,ls:1,rf:1,rs:1,a:5
[5/5]ccabb5lf:5,rf:1,a:7
[5/6]acccc5lf:4,ls:1,rf:2,rp:1,rs:1,a:6

Considering [length 3 / frequency 1] bbb=d.

Step 3

Rewriting system is complete. See ⟨a, b | abaabbba=baa⟩.