Morphocompletion for #4801 ⟨a, b | abaabbab=aba⟩

Solved by morph:4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abaabbab ⇒ aba
2. abaaabbab ⇒ abaa
3. abaaaabbab ⇒ abaaa
4. abaaaaabbab ⇒ abaaaa
5. abaaaaaabbab ⇒ abaaaaa
6. abaaaaaaabbab ⇒ abaaaaaa
7. abaaaaaaaabbab ⇒ abaaaaaaa
8. abaaaaaaaaabbab ⇒ abaaaaaaaa
9. abaaaaaaaaaabbab ⇒ abaaaaaaaaa
10. abaaaaaaaaaaabbab ⇒ abaaaaaaaaaa
11. abaaaaaaaaaaaabbab ⇒ abaaaaaaaaaaa
12. abaaaaaaaaaaaaabbab ⇒ abaaaaaaaaaaaa
13. abaaaaaaaaaaaaaabbab ⇒ abaaaaaaaaaaaaa
14. abaaaaaaaaaaaaaaabbab ⇒ abaaaaaaaaaaaaaa
15. abaaaaaaaaaaaaaaaabbab ⇒ abaaaaaaaaaaaaaaa
16. abaaaaaaaaaaaaaaaaabbab ⇒ abaaaaaaaaaaaaaaaa
17. abaaaaaaaaaaaaaaaaaabbab ⇒ abaaaaaaaaaaaaaaaaa
18. abaaaaaaaaaaaaaaaaaaabbab ⇒ abaaaaaaaaaaaaaaaaaa
19. abaaaaaaaaaaaaaaaaaaaabbab ⇒ abaaaaaaaaaaaaaaaaaaa
20. abaaaaaaaaaaaaaaaaaaaaabbab ⇒ abaaaaaaaaaaaaaaaaaaaa
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa210lf:210,rf:190,rs:19
[2/1]ab100lf:60,lp:20,ls:20,rf:20,rp:20,lprp:20,lsrp:20
[2/2]ba40lf:40,rf:20,rs:1
[2/3]bb20lf:20
[3/0]aaa190lf:190,rf:171,rs:18,a:1
[3/1]aba40lf:20,lp:20,rf:20,rp:20,rs:1,re:1,lprp:20,lprs:1
[3/2]bab40lf:20,ls:20
[3/3]baa20lf:20,rf:19,rs:1
[3/4]aab20lf:20
[3/5]bba20lf:20
[3/6]abb20lf:20
[4/0]aaaa171lf:171,rf:153,rs:17,a:2
[4/1]abaa40lf:20,lp:20,rf:19,rp:19,rs:1,re:1,lprp:19,lprs:1
[4/2]bbab40lf:20,ls:20
[4/3]abba20lf:20
[4/4]aabb20lf:20
[4/5]baaa19lf:19,rf:18,rs:1,a:1
[4/6]aaab19lf:19,a:1
[5/0]aaaaa153lf:153,rf:136,rs:16,a:3
[5/1]abbab40lf:20,ls:20
[5/2]abaaa38lf:19,lp:19,rf:18,rp:18,rs:1,re:1,lprp:18,lprs:1,a:1
[5/3]aabba20lf:20
[5/4]aaabb19lf:19,a:1
[5/5]baaaa18lf:18,rf:17,rs:1,a:2
[5/6]aaaab18lf:18,a:2
[6/0]aaaaaa136lf:136,rf:120,rs:15,a:4
[6/1]aabbab40lf:20,ls:20
[6/2]abaaaa36lf:18,lp:18,rf:17,rp:17,rs:1,re:1,lprp:17,lprs:1,a:2
[6/3]aaabba19lf:19,a:1
[6/4]aaaabb18lf:18,a:2
[6/5]baaaaa17lf:17,rf:16,rs:1,a:3
[6/6]aaaaab17lf:17,a:3
[7/0]aaaaaaa120lf:120,rf:105,rs:14,a:5
[7/1]aaabbab38lf:19,ls:19,a:1
[7/2]abaaaaa34lf:17,lp:17,rf:16,rp:16,rs:1,re:1,lprp:16,lprs:1,a:3
[7/3]aaaabba18lf:18,a:2
[7/4]aaaaabb17lf:17,a:3
[7/5]baaaaaa16lf:16,rf:15,rs:1,a:4
[7/6]aaaaaab16lf:16,a:4

Considering [length 4 / frequency 1] abaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaabbab=aba⟩.