Morphocompletion for #4795 ⟨a, b | abaababa=baa

Solved by morph:3/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaababa ⇒ baa
2. abaabbaa ⇒ baaababa
3. abaababbaa ⇒ babaa
4. abaabbabaa ⇒ baaababbaa
5. abaababbbaa ⇒ babbaa
6. abaababbabaa ⇒ bababaa
7. abaababbabbaa ⇒ bababbaa
8. abaababbbabaa ⇒ babbabaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] baa, [3/2] bab, [3/3] bba
Length 4:[4/0] abaa, [4/1] bbaa, [4/2] baab, [4/3] babb
Length 5:[5/0] abaab, [5/1] babaa, [5/2] abbaa, [5/3] baaba
Length 6:[6/0] abaaba, [6/1] bbabaa, [6/2] baabab, [6/3] aababb

Considering [length 3 / frequency 0] aba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aba ⇒ c
2. accba ⇒ ca
3. accccba ⇒ caa
4. accccccba ⇒ caaa
5. baa ⇒ ccba
6. abc ⇒ cba
7. accbc ⇒ cc
8. accccbc ⇒ cac
9. accccccbc ⇒ caac
10. bac ⇒ ccbc
11. ccbccba ⇒ bca
12. ccbccccba ⇒ bcaa
13. ccbccbc ⇒ bcc
14. ccbccccbc ⇒ bcac
15. ccbbca ⇒ bcccba
16. ccbbcc ⇒ bcccbc
17. accbbbca ⇒ cbbca
18. babbca ⇒ ccbbbca
19. accbbbcc ⇒ cbbcc
20. babbcc ⇒ ccbbbcc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] cc, [2/1] bc, [2/2] ba, [2/3] cb, [2/4] ac, [2/5] bb, [2/6] ab
Length 3:[3/0] ccb, [3/1] ccc, [3/2] acc, [3/3] cbc, [3/4] bcc, [3/5] cba, [3/6] bbc
Length 4:[4/0] ccbc, [4/1] ccba, [4/2] cccc, [4/3] accb, [4/4] accc, [4/5] bbcc, [4/6] bbca
Length 5:[5/0] ccbcc, [5/1] acccc, [5/2] cccbc, [5/3] cccba, [5/4] ccccb, [5/5] babbc, [5/6] ccbbc

Considering [length 3 / frequency 0] ccb=d.

Step 3

Rewriting system is complete. See a, b | abaababa=baa.