Morphocompletion for #4792 ⟨a, b | abaababa=aab

Solved by morph:5/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaababa ⇒ aab
2. aabbaaba ⇒ ababaaab
3. aabababa ⇒ abaabaab
4. aababaab ⇒ abaaabba
5. aabaabba ⇒ abaaabab
6. ababaabaab ⇒ aabba
7. ababaaabba ⇒ aabab
8. abaaabbaaab ⇒ aaabba
9. aabbabaaba ⇒ abaabbaaab
10. abababaaabab ⇒ aabbaba
11. aabbabaaabba ⇒ aababab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] bab, [3/3] baa, [3/4] bba, [3/5] abb, [3/6] aaa
Length 4:[4/0] abab, [4/1] aaba, [4/2] baba, [4/3] abaa, [4/4] aabb, [4/5] abba, [4/6] baab
Length 5:[5/0] aabba, [5/1] ababa, [5/2] abaab, [5/3] aabab, [5/4] baaab, [5/5] baaba, [5/6] babaa
Length 6:[6/0] aababa, [6/1] ababaa, [6/2] aaabba, [6/3] abaaab, [6/4] abaaba, [6/5] aabbab, [6/6] babaab
Length 7:[7/0] baaabba, [7/1] aabbaba, [7/2] abaaabb, [7/3] ababaab, [7/4] abababa, [7/5] babaaab, [7/6] babaaba

Considering [length 5 / frequency 1] ababa=c.

Step 2

Rewriting system is complete. See a, b | abaababa=aab.