| Back: | ⟨a, b | abaababa=aab⟩ |
|---|
Solved by morph:5/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abaababa ⇒ aab |
| 2. | aabbaaba ⇒ ababaaab |
| 3. | aabababa ⇒ abaabaab |
| 4. | aababaab ⇒ abaaabba |
| 5. | aabaabba ⇒ abaaabab |
| 6. | ababaabaab ⇒ aabba |
| 7. | ababaaabba ⇒ aabab |
| 8. | abaaabbaaab ⇒ aaabba |
| 9. | aabbabaaba ⇒ abaabbaaab |
| 10. | abababaaabab ⇒ aabbaba |
| 11. | aabbabaaabba ⇒ aababab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 43 | lf:34,lp:5,ls:4,rf:24,rp:5,rs:7,lsrp:1,lprs:2 |
|---|---|---|---|
| [2/1] | ba | 37 | lf:30,ls:7,rf:17,rs:4 |
| [2/2] | aa | 29 | lf:23,lp:6,rf:18,rp:6,lprp:1 |
| [2/3] | bb | 7 | lf:7,rf:5,a:6 |
| [3/0] | aba | 32 | lf:23,lp:5,ls:4,rf:12,rp:5,rs:1,lsrp:3,lprs:1 |
| [3/1] | aab | 27 | lf:18,lp:6,ls:3,rf:13,rp:5,rs:4,re:1,lprp:1,lsrp:1,lprs:3 |
| [3/2] | bab | 12 | lf:11,ls:1,rf:6,rs:3 |
| [3/3] | baa | 12 | lf:12,rf:7 |
| [3/4] | bba | 10 | lf:7,ls:3,rf:5,rs:3,a:6 |
| [3/5] | abb | 7 | lf:7,rf:5,a:6 |
| [3/6] | aaa | 5 | lf:5,rf:5,rp:1,a:7 |
| [4/0] | abab | 13 | lf:9,lp:3,ls:1,rf:5,rp:1,rs:3,lprs:1 |
| [4/1] | aaba | 13 | lf:8,lp:3,ls:2,rf:4,rp:2 |
| [4/2] | baba | 12 | lf:10,ls:2,rf:3,rs:1 |
| [4/3] | abaa | 12 | lf:10,lp:2,rf:6,rp:4 |
| [4/4] | aabb | 10 | lf:7,lp:3,rf:5,rp:2,a:6 |
| [4/5] | abba | 10 | lf:7,ls:3,rf:5,rs:3,a:6 |
| [4/6] | baab | 9 | lf:7,ls:2,rf:3,rs:1 |
| [5/0] | aabba | 13 | lf:7,lp:3,ls:3,rf:5,rp:2,rs:3,re:1,a:6 |
| [5/1] | ababa | 13 | lf:8,lp:3,ls:2,rf:2,rp:1 |
| [5/2] | abaab | 9 | lf:6,lp:1,ls:2,rf:3,rp:2,rs:1 |
| [5/3] | aabab | 7 | lf:4,lp:2,ls:1,rf:3,rp:2,rs:2,re:1 |
| [5/4] | baaab | 6 | lf:5,ls:1,rf:4,rs:2,a:7 |
| [5/5] | baaba | 6 | lf:4,ls:2,rf:1 |
| [5/6] | babaa | 6 | lf:6,rf:1,a:6 |
| [6/0] | aababa | 6 | lf:3,lp:2,ls:1,rf:1,rp:1 |
| [6/1] | ababaa | 6 | lf:4,lp:2,rf:1,rp:1,a:6 |
| [6/2] | aaabba | 5 | lf:3,ls:2,rf:2,rp:1,rs:2,re:1,a:7 |
| [6/3] | abaaab | 5 | lf:4,lp:1,rf:3,rp:2,rs:1,a:7 |
| [6/4] | abaaba | 5 | lf:3,lp:1,ls:1,rf:1,rp:1 |
| [6/5] | aabbab | 4 | lf:2,lp:2,rf:1,rp:1,a:18 |
| [6/6] | babaab | 4 | lf:3,ls:1,a:6 |
| [7/0] | baaabba | 5 | lf:3,ls:2,rf:1,rs:1,a:7 |
| [7/1] | aabbaba | 4 | lf:2,lp:2,rf:1,rp:1,rs:1,re:1,a:18 |
| [7/2] | abaaabb | 4 | lf:3,lp:1,rf:1,rp:1,a:7 |
| [7/3] | ababaab | 4 | lf:2,lp:1,ls:1,a:6 |
| [7/4] | abababa | 4 | lf:2,lp:1,ls:1,a:1 |
| [7/5] | babaaab | 3 | lf:3,rf:1,rs:1,a:13 |
| [7/6] | babaaba | 3 | lf:2,ls:1,a:6 |
Considering [length 5 / frequency 1] ababa=c.
Rewriting system is complete. See ⟨a, b | abaababa=aab⟩.