| Back: | ⟨a, b | abbaab=aa⟩ |
|---|
Solved by morph:3/2. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abbaab ⇒ aa |
| 2. | aabaab ⇒ abbaaa |
| 3. | abbabbaaa ⇒ aaaab |
| 4. | aababbaaa ⇒ abbaaaaab |
| 5. | aaaabbbaab ⇒ aaaaba |
| 6. | aaaababaab ⇒ aaaabbbaaa |
| 7. | aaaababbbaab ⇒ aaaababa |
| 8. | aaaabababaab ⇒ aaaababbbaaa |
| 9. | aaaabbbabbaaa ⇒ aaaabaaab |
| 10. | aaaabababbaaa ⇒ aaaabbbaaaaab |
| 11. | aaaabababbbaab ⇒ aaaabababa |
| 12. | aaaabaaabbbaab ⇒ aaaabaaaba |
| 13. | aaaababbbabbaaa ⇒ aaaababaaab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 65 | lf:49,lp:11,ls:5,rf:51,rp:11,rs:4,re:1,lprp:9,lsrp:4,lprs:3 |
|---|---|---|---|
| [2/1] | ab | 45 | lf:35,lp:2,ls:8,rf:22,rp:2,rs:5,lsrp:1,lprs:1 |
| [2/2] | ba | 27 | lf:27,rf:17,rs:4 |
| [2/3] | bb | 19 | lf:19,rf:8 |
| [3/0] | aaa | 38 | lf:24,lp:9,ls:5,rf:32,rp:10,rs:3,lprp:9,lsrp:4,lprs:2,a:1 |
| [3/1] | aab | 30 | lf:20,lp:2,ls:8,rf:15,rs:5,lprs:1 |
| [3/2] | abb | 15 | lf:13,lp:2,rf:5,rp:2 |
| [3/3] | aba | 14 | lf:14,rf:12,rs:4,a:1 |
| [3/4] | baa | 14 | lf:14,rf:8 |
| [3/5] | bab | 13 | lf:13,rf:5,a:2 |
| [3/6] | bba | 13 | lf:13,rf:5 |
| [4/0] | aaaa | 18 | lf:9,lp:9,rf:14,rp:10,lprp:9,a:2 |
| [4/1] | baab | 16 | lf:8,ls:8 |
| [4/2] | aaba | 11 | lf:9,lp:2,rf:8,rs:2,a:1 |
| [4/3] | baaa | 11 | lf:6,ls:5,rf:8,rs:3,a:1 |
| [4/4] | aaab | 10 | lf:10,rf:15,rs:5,a:2 |
| [4/5] | abab | 10 | lf:10,rf:5,a:3 |
| [4/6] | bbaa | 10 | lf:10,rf:5 |
| [5/0] | aaaab | 18 | lf:9,lp:9,rf:12,rp:10,rs:3,re:1,lprp:9,lprs:1,a:2 |
| [5/1] | bbaaa | 10 | lf:5,ls:5,rf:5,rs:3,a:1 |
| [5/2] | bbaab | 10 | lf:5,ls:5 |
| [5/3] | aabab | 8 | lf:7,lp:1,rf:4,a:3 |
| [5/4] | aaaba | 7 | lf:7,rf:8,rs:2,a:4 |
| [5/5] | abbaa | 7 | lf:6,lp:1,rf:2,rp:2 |
| [5/6] | abaab | 6 | lf:3,ls:3,a:1 |
| [6/0] | aaaaba | 14 | lf:7,lp:7,rf:7,rp:7,rs:1,re:1,lprp:5,a:4 |
| [6/1] | abbaaa | 10 | lf:5,ls:5,rf:2,rp:2,rs:1,re:1,lsrp:1,a:1 |
| [6/2] | bbbaab | 8 | lf:4,ls:4,a:4 |
| [6/3] | aaabab | 6 | lf:6,rf:4,a:5 |
| [6/4] | babbaa | 5 | lf:5,a:2 |
| [6/5] | aaaabb | 4 | lf:2,lp:2,rf:2,rp:2,a:4 |
| [6/6] | aababa | 4 | lf:4,rf:3,rs:1,a:5 |
| [7/0] | aaaabab | 12 | lf:6,lp:6,rf:4,rp:4,lprp:4,a:5 |
| [7/1] | babbaaa | 10 | lf:5,ls:5,a:2 |
| [7/2] | abbbaab | 8 | lf:4,ls:4,a:4 |
| [7/3] | aaaabbb | 4 | lf:2,lp:2,rf:2,rp:2,a:4 |
| [7/4] | aaababa | 4 | lf:4,rf:3,rs:1,a:5 |
| [7/5] | ababaab | 4 | lf:2,ls:2,a:5 |
| [7/6] | aaabbba | 3 | lf:3,rf:2,a:4 |
Considering [length 3 / frequency 2] abb=c.
Rewriting system is complete. See ⟨a, b | abbaab=aa⟩.