Morphocompletion for #479 ⟨a, b | abbaab=aa⟩

Back:⟨a, b | abbaab=aa⟩

Solved by morph:3/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaab ⇒ aa
2. aabaab ⇒ abbaaa
3. abbabbaaa ⇒ aaaab
4. aababbaaa ⇒ abbaaaaab
5. aaaabbbaab ⇒ aaaaba
6. aaaababaab ⇒ aaaabbbaaa
7. aaaababbbaab ⇒ aaaababa
8. aaaabababaab ⇒ aaaababbbaaa
9. aaaabbbabbaaa ⇒ aaaabaaab
10. aaaabababbaaa ⇒ aaaabbbaaaaab
11. aaaabababbbaab ⇒ aaaabababa
12. aaaabaaabbbaab ⇒ aaaabaaaba
13. aaaababbbabbaaa ⇒ aaaababaaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] abb, [3/3] aba, [3/4] baa, [3/5] bab, [3/6] bba
Length 4:[4/0] aaaa, [4/1] baab, [4/2] aaba, [4/3] baaa, [4/4] aaab, [4/5] abab, [4/6] bbaa
Length 5:[5/0] aaaab, [5/1] bbaaa, [5/2] bbaab, [5/3] aabab, [5/4] aaaba, [5/5] abbaa, [5/6] abaab
Length 6:[6/0] aaaaba, [6/1] abbaaa, [6/2] bbbaab, [6/3] aaabab, [6/4] babbaa, [6/5] aaaabb, [6/6] aababa
Length 7:[7/0] aaaabab, [7/1] babbaaa, [7/2] abbbaab, [7/3] aaaabbb, [7/4] aaababa, [7/5] ababaab, [7/6] aaabbba

Considering [length 3 / frequency 2] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbaab=aa⟩.