Morphocompletion for #4789 ⟨a, b | abaabaab=bba

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abaabaab ⇒ bba
2. ababba ⇒ bbaaab
3. bbaaabbaabaab ⇒ ababbbba
4. bbaaabbabba ⇒ ababbbbaaab
5. bbaaabaabbaabaab ⇒ abaababbbba
6. abaabaaababbbba ⇒ bbabaaabbaabaab
7. bbaaabaabbabba ⇒ abaababbbbaaab
8. abaabaaabaababbbba ⇒ bbabaaabaabbaabaab
9. bbabaaabbaabaabbaabaab ⇒ abaabaaababbbbbba
10. bbaaabbaabaaababbbba ⇒ ababbbbabaaabbaabaab
11. bbabaaabbaabaabbabba ⇒ abaabaaababbbbbbaaab
12. bbabaaabaabbaabaabbaabaab ⇒ abaabaaabaababbbbbba
13. abaabaaabaabaaababbbbbba ⇒ bbababaaabbaabaabbaabaab
14. bbaaabbaabaaabaababbbba ⇒ ababbbbabaaabaabbaabaab
15. bbaaabaabbaabaaababbbba ⇒ abaababbbbabaaabbaabaab
16. bbabaaabaabbaabaabbabba ⇒ abaabaaabaababbbbbbaaab
17. abaabaaabaabaaabaababbbbbba ⇒ bbababaaabaabbaabaabbaabaab
18. bbaaabaabbaabaaabaababbbba ⇒ abaababbbbabaaabaabbaabaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] bba, [3/1] aab, [3/2] baa, [3/3] aba, [3/4] abb, [3/5] aaa, [3/6] bbb
Length 4:[4/0] abaa, [4/1] baab, [4/2] aaba, [4/3] bbaa, [4/4] abba, [4/5] baaa, [4/6] aaab
Length 5:[5/0] abaab, [5/1] aabaa, [5/2] baaba, [5/3] baaab, [5/4] bbbba, [5/5] bbaaa, [5/6] aabba
Length 6:[6/0] aabaab, [6/1] baabaa, [6/2] bbaaab, [6/3] baaaba, [6/4] abaaba, [6/5] abaaab, [6/6] abbbba
Length 7:[7/0] baabaab, [7/1] babbbba, [7/2] bbaabaa, [7/3] abbaaba, [7/4] aabbaab, [7/5] baaabaa, [7/6] abaabaa

Considering [length 2 / frequency 0] ba=c.

Step 2

Rewriting system is complete. See a, b | abaabaab=bba.