| Back: | ⟨a, b | abaabaab=bab⟩ |
|---|
Solved by morph:2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | ababab ⇒ babaab |
| 2. | abaabaab ⇒ bab |
| 3. | abbabaab ⇒ babaabab |
| 4. | ababbab ⇒ bbabaab |
| 5. | babaababaab ⇒ abbbab |
| 6. | abbbbab ⇒ bbbabab |
| 7. | abbbabaab ⇒ babaabbab |
| 8. | ababbbab ⇒ bbbabaab |
| 9. | abaabbbab ⇒ bbababaab |
| 10. | abbbbbab ⇒ bbbabbab |
| 11. | abbbbbbab ⇒ bbbabbbab |
| 12. | abbbabbbab ⇒ bbbaabbbab |
| 13. | abbbbbbbab ⇒ bbbbbbabab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 61 | lf:36,lp:12,ls:13,rf:28,rp:1,rs:13,lsrp:1,lprs:12,lsrs:13 |
|---|---|---|---|
| [2/1] | bb | 30 | lf:30,rf:25,rp:8,a:2 |
| [2/2] | ba | 25 | lf:24,lp:1,rf:27,rp:4 |
| [2/3] | aa | 7 | lf:7,rf:7 |
| [3/0] | bab | 27 | lf:17,lp:1,ls:9,rf:20,rp:4,rs:9,re:1,lsrp:1,lprs:1,lsrs:5 |
| [3/1] | bbb | 19 | lf:19,rf:12,rp:6,a:4 |
| [3/2] | abb | 18 | lf:11,lp:7,rf:5,rp:1,a:2 |
| [3/3] | aba | 17 | lf:12,lp:5,rf:10 |
| [3/4] | bba | 11 | lf:11,rf:13,rp:2,a:2 |
| [3/5] | aab | 11 | lf:7,ls:4,rf:7,rs:4 |
| [3/6] | baa | 7 | lf:7,rf:7 |
| [4/0] | bbab | 19 | lf:11,ls:8,rf:12,rp:2,rs:5,lsrp:2,lsrs:3,a:2 |
| [4/1] | abbb | 15 | lf:9,lp:6,rf:3,rp:1,a:4 |
| [4/2] | baab | 11 | lf:7,ls:4,rf:7,rs:4 |
| [4/3] | bbbb | 10 | lf:10,rf:3,rp:1,a:8 |
| [4/4] | bbba | 9 | lf:9,rf:9,rp:5,a:4 |
| [4/5] | abab | 9 | lf:5,lp:3,ls:1,rf:4,rs:3,a:1 |
| [4/6] | abaa | 9 | lf:7,lp:2,rf:6 |
| [5/0] | bbbab | 16 | lf:9,ls:7,rf:8,rp:4,rs:3,lsrp:4,lsrs:2,a:4 |
| [5/1] | abaab | 13 | lf:7,lp:2,ls:4,rf:6,rs:4,lprs:1 |
| [5/2] | abbbb | 8 | lf:4,lp:4,a:8 |
| [5/3] | abbba | 7 | lf:5,lp:2,rf:3,rp:1,a:4 |
| [5/4] | bbbbb | 6 | lf:6,rf:2,rp:1,a:8 |
| [5/5] | babaa | 5 | lf:4,lp:1,rf:6,rp:3,a:1 |
| [5/6] | bbbba | 4 | lf:4,rf:1,a:8 |
| [6/0] | abbbab | 10 | lf:5,lp:2,ls:3,rf:3,rp:1,rs:3,re:1,lprs:1,lsrs:1,a:4 |
| [6/1] | bbbbab | 8 | lf:4,ls:4,rf:1,a:8 |
| [6/2] | babaab | 8 | lf:4,lp:1,ls:3,rf:6,rp:3,rs:4,re:1,lsrp:2,a:1 |
| [6/3] | abbbbb | 6 | lf:3,lp:3,a:8 |
| [6/4] | bbbbbb | 3 | lf:3,rf:1,rp:1,a:15 |
| [6/5] | bbbbba | 3 | lf:3,rf:1,a:8 |
| [6/6] | abaaba | 3 | lf:2,lp:1,rf:1 |
| [7/0] | bbbbbab | 6 | lf:3,ls:3,rf:1,a:8 |
| [7/1] | abbbbbb | 4 | lf:2,lp:2,a:15 |
| [7/2] | babbbab | 4 | lf:2,ls:2,rf:1,rs:1,a:5 |
| [7/3] | bbabaab | 4 | lf:2,ls:2,rf:2,rp:1,rs:2,re:1,a:2 |
| [7/4] | bbbbbba | 2 | lf:2,rf:1,rp:1,a:15 |
| [7/5] | abbbabb | 2 | lf:1,lp:1,a:29 |
| [7/6] | abbbbba | 2 | lf:1,lp:1,a:8 |
Considering [length 2 / frequency 0] ab=c.
Rewriting system is complete. See ⟨a, b | abaabaab=bab⟩.