| Back: | ⟨a, b | abaaabba=baa⟩ |
|---|
Solved by morph:4/1,4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abaaabba ⇒ baa |
| 2. | abaaabbbaa ⇒ babaa |
| 3. | abaaabbbbaa ⇒ babbaa |
| 4. | abaaabbbabaa ⇒ bababaa |
| 5. | abaaabbbbbaa ⇒ babbbaa |
| 6. | abaaabbbbabaa ⇒ babbabaa |
| 7. | abaaabbbabbaa ⇒ bababbaa |
| 8. | abaaabbbababaa ⇒ babababaa |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb |
|---|---|
| Length 3: | [3/0] baa, [3/1] aba, [3/2] bbb, [3/3] bba |
| Length 4: | [4/0] abaa, [4/1] aabb, [4/2] bbaa, [4/3] aaab |
| Length 5: | [5/0] abaaa, [5/1] aaabb, [5/2] baaab, [5/3] aabbb |
| Length 6: | [6/0] abaaab, [6/1] baaabb, [6/2] aaabbb, [6/3] bbbbaa |
Considering [length 4 / frequency 1] aabb=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | abaca ⇒ baa |
| 2. | aabb ⇒ c |
| 3. | abacc ⇒ bac |
| 4. | abacbaa ⇒ babaa |
| 5. | abacbc ⇒ babc |
| 6. | abacbac ⇒ babac |
| 7. | abacbbaa ⇒ babbaa |
| 8. | abacbabaa ⇒ bababaa |
| 9. | abacbbc ⇒ babbc |
| 10. | abacbbac ⇒ babbac |
| 11. | abacbabc ⇒ bababc |
| 12. | abacbabac ⇒ bababac |
| 13. | abacbbbaa ⇒ babbbaa |
| 14. | abacbbabaa ⇒ babbabaa |
| 15. | abacbabbaa ⇒ bababbaa |
| 16. | abacbbbc ⇒ babbbc |
| 17. | abacbbbac ⇒ babbbac |
| 18. | abacbbabc ⇒ babbabc |
| 19. | abacbbabac ⇒ babbabac |
| 20. | abacbabbc ⇒ bababbc |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] ab, [2/1] ba, [2/2] ac, [2/3] cb, [2/4] bb, [2/5] aa, [2/6] bc |
|---|---|
| Length 3: | [3/0] aba, [3/1] bac, [3/2] acb, [3/3] baa, [3/4] cbb, [3/5] bab, [3/6] bba |
| Length 4: | [4/0] abac, [4/1] bacb, [4/2] acbb, [4/3] acba, [4/4] bbaa, [4/5] cbab, [4/6] cbba |
| Length 5: | [5/0] abacb, [5/1] bacbb, [5/2] bacba, [5/3] acbab, [5/4] acbba, [5/5] babac, [5/6] babaa |
Considering [length 4 / frequency 0] abac=d.
Rewriting system is complete. See ⟨a, b | abaaabba=baa⟩.