Morphocompletion for #4779 ⟨a, b | abaaabba=baa

Solved by morph:4/1,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaabba ⇒ baa
2. abaaabbbaa ⇒ babaa
3. abaaabbbbaa ⇒ babbaa
4. abaaabbbabaa ⇒ bababaa
5. abaaabbbbbaa ⇒ babbbaa
6. abaaabbbbabaa ⇒ babbabaa
7. abaaabbbabbaa ⇒ bababbaa
8. abaaabbbababaa ⇒ babababaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] baa, [3/1] aba, [3/2] bbb, [3/3] bba
Length 4:[4/0] abaa, [4/1] aabb, [4/2] bbaa, [4/3] aaab
Length 5:[5/0] abaaa, [5/1] aaabb, [5/2] baaab, [5/3] aabbb
Length 6:[6/0] abaaab, [6/1] baaabb, [6/2] aaabbb, [6/3] bbbbaa

Considering [length 4 / frequency 1] aabb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abaca ⇒ baa
2. aabb ⇒ c
3. abacc ⇒ bac
4. abacbaa ⇒ babaa
5. abacbc ⇒ babc
6. abacbac ⇒ babac
7. abacbbaa ⇒ babbaa
8. abacbabaa ⇒ bababaa
9. abacbbc ⇒ babbc
10. abacbbac ⇒ babbac
11. abacbabc ⇒ bababc
12. abacbabac ⇒ bababac
13. abacbbbaa ⇒ babbbaa
14. abacbbabaa ⇒ babbabaa
15. abacbabbaa ⇒ bababbaa
16. abacbbbc ⇒ babbbc
17. abacbbbac ⇒ babbbac
18. abacbbabc ⇒ babbabc
19. abacbbabac ⇒ babbabac
20. abacbabbc ⇒ bababbc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] ac, [2/3] cb, [2/4] bb, [2/5] aa, [2/6] bc
Length 3:[3/0] aba, [3/1] bac, [3/2] acb, [3/3] baa, [3/4] cbb, [3/5] bab, [3/6] bba
Length 4:[4/0] abac, [4/1] bacb, [4/2] acbb, [4/3] acba, [4/4] bbaa, [4/5] cbab, [4/6] cbba
Length 5:[5/0] abacb, [5/1] bacbb, [5/2] bacba, [5/3] acbab, [5/4] acbba, [5/5] babac, [5/6] babaa

Considering [length 4 / frequency 0] abac=d.

Step 3

Rewriting system is complete. See a, b | abaaabba=baa.