Morphocompletion for #4773 ⟨a, b | abaaabab=bba

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abaaabab ⇒ bba
2. abaaabbba ⇒ bbaaaabab
3. bbaaaababbaaabab ⇒ abaaabbbbba
4. abaaabaabaaabbbbba ⇒ bbabaaaababbaaabab
5. bbaaaababbaaabbba ⇒ abaaabbbbbaaaabab
6. bbabaaaababbaaababbaaabab ⇒ abaaabaabaaabbbbbbba
7. abaaabaabaaabaabaaabbbbbbba ⇒ bbababaaaababbaaababbaaabab
8. bbaaaababbaaabaabaaabbbbba ⇒ abaaabbbbbabaaaababbaaabab
9. bbabaaaababbaaababbaaabbba ⇒ abaaabaabaaabbbbbbbaaaabab
10. bbababaaaababbaaababbaaababbaaabab ⇒ abaaabaabaaabaabaaabbbbbbbbba
11. abaaabaabaaabaabaaabaabaaabbbbbbbbba ⇒ bbabababaaaababbaaababbaaababbaaabab
12. bbaaaababbaaabaabaaabaabaaabbbbbbba ⇒ abaaabbbbbababaaaababbaaababbaaabab
13. bbabaaaababbaaababbaaabaabaaabbbbba ⇒ abaaabaabaaabbbbbbbabaaaababbaaabab
14. bbababaaaababbaaababbaaababbaaabbba ⇒ abaaabaabaaabaabaaabbbbbbbbbaaaabab
15. bbabababaaaababbaaababbaaababbaaababbaaabab ⇒ abaaabaabaaabaabaaabaabaaabbbbbbbbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] aa, [2/2] ab, [2/3] bb
Length 3:[3/0] aba, [3/1] bba, [3/2] baa, [3/3] aab, [3/4] aaa, [3/5] bab, [3/6] bbb
Length 4:[4/0] baaa, [4/1] aaba, [4/2] aaab, [4/3] abaa, [4/4] abab, [4/5] bbaa, [4/6] bbbb
Length 5:[5/0] baaab, [5/1] aaaba, [5/2] aabab, [5/3] bbaaa, [5/4] abaaa, [5/5] babba, [5/6] ababb
Length 6:[6/0] aaabab, [6/1] baaaba, [6/2] babbaa, [6/3] ababba, [6/4] bbaaab, [6/5] aababb, [6/6] abbaaa
Length 7:[7/0] babbaaa, [7/1] ababbaa, [7/2] aababba, [7/3] abbaaab, [7/4] baaabab, [7/5] aaababb, [7/6] bbaaaba

Considering [length 2 / frequency 0] ba=c.

Step 2

Rewriting system is complete. See a, b | abaaabab=bba.