Morphocompletion for #4769 ⟨a, b | abaaabab=aba⟩

Back:⟨a, b | abaaabab=aba⟩

Solved by morph:5/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abaaabab ⇒ aba
2. abaaaabab ⇒ abaa
3. abaaaaabab ⇒ abaaa
4. abaaaaaabab ⇒ abaaaa
5. abaaaaaaabab ⇒ abaaaaa
6. abaaaaaaaabab ⇒ abaaaaaa
7. abaaaaaaaaabab ⇒ abaaaaaaa
8. abaaaaaaaaaabab ⇒ abaaaaaaaa
9. abaaaaaaaaaaabab ⇒ abaaaaaaaaa
10. abaaaaaaaaaaaabab ⇒ abaaaaaaaaaa
11. abaaaaaaaaaaaaabab ⇒ abaaaaaaaaaaa
12. abaaaaaaaaaaaaaabab ⇒ abaaaaaaaaaaaa
13. abaaaaaaaaaaaaaaabab ⇒ abaaaaaaaaaaaaa
14. abaaaaaaaaaaaaaaaabab ⇒ abaaaaaaaaaaaaaa
15. abaaaaaaaaaaaaaaaaabab ⇒ abaaaaaaaaaaaaaaa
16. abaaaaaaaaaaaaaaaaaabab ⇒ abaaaaaaaaaaaaaaaa
17. abaaaaaaaaaaaaaaaaaaabab ⇒ abaaaaaaaaaaaaaaaaa
18. abaaaaaaaaaaaaaaaaaaaabab ⇒ abaaaaaaaaaaaaaaaaaa
19. abaaaaaaaaaaaaaaaaaaaaabab ⇒ abaaaaaaaaaaaaaaaaaaa
20. abaaaaaaaaaaaaaaaaaaaaaabab ⇒ abaaaaaaaaaaaaaaaaaaaa
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa230lf:230,rf:190,rs:19
[2/1]ab100lf:60,lp:20,ls:20,rf:20,rp:20,lprp:20,lsrp:20
[2/2]ba40lf:40,rf:20,rs:1
[3/0]aaa210lf:210,rf:171,rs:18
[3/1]aba60lf:40,lp:20,rf:20,rp:20,rs:1,re:1,lprp:20,lprs:1
[3/2]bab40lf:20,ls:20
[3/3]baa20lf:20,rf:19,rs:1
[3/4]aab20lf:20
[4/0]aaaa190lf:190,rf:153,rs:17,a:1
[4/1]abaa40lf:20,lp:20,rf:19,rp:19,rs:1,re:1,lprp:19,lprs:1
[4/2]abab40lf:20,ls:20
[4/3]baaa20lf:20,rf:18,rs:1
[4/4]aaba20lf:20
[4/5]aaab20lf:20
[5/0]aaaaa171lf:171,rf:136,rs:16,a:2
[5/1]abaaa40lf:20,lp:20,rf:18,rp:18,rs:1,re:1,lprp:18,lprs:1
[5/2]aabab40lf:20,ls:20
[5/3]aaaba20lf:20
[5/4]baaaa19lf:19,rf:17,rs:1,a:1
[5/5]aaaab19lf:19,a:1
[5/6]baaab1lf:1
[6/0]aaaaaa153lf:153,rf:120,rs:15,a:3
[6/1]aaabab40lf:20,ls:20
[6/2]abaaaa38lf:19,lp:19,rf:17,rp:17,rs:1,re:1,lprp:17,lprs:1,a:1
[6/3]aaaaba19lf:19,a:1
[6/4]baaaaa18lf:18,rf:16,rs:1,a:2
[6/5]aaaaab18lf:18,a:2
[6/6]abaaab2lf:1,lp:1
[7/0]aaaaaaa136lf:136,rf:105,rs:14,a:4
[7/1]aaaabab38lf:19,ls:19,a:1
[7/2]abaaaaa36lf:18,lp:18,rf:16,rp:16,rs:1,re:1,lprp:16,lprs:1,a:2
[7/3]aaaaaba18lf:18,a:2
[7/4]baaaaaa17lf:17,rf:15,rs:1,a:3
[7/5]aaaaaab17lf:17,a:3
[7/6]abaaaba2lf:1,lp:1

Considering [length 5 / frequency 1] abaaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaabab=aba⟩.