Morphocompletion for #4768 ⟨a, b | abaaabab=aab⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaabab ⇒ abaaaab
2. aaaabaab ⇒ abaaaaab
3. aaaabaaab ⇒ abaaaaaab
4. aaaabaaaab ⇒ abaaaaaaab
5. aaaabaaaaab ⇒ abaaaaaaaab
6. aaaabaaaaaab ⇒ abaaaaaaaaab
7. aaaabaaaaaaab ⇒ abaaaaaaaaaab
8. aaaabaaaaaaaab ⇒ abaaaaaaaaaaab
9. aaaabaaaaaaaaab ⇒ abaaaaaaaaaaaab
10. abaaabab ⇒ aab
11. abaaabaab ⇒ aaab
12. abaaabaaab ⇒ aaaab
13. abaaabaaaab ⇒ aaaaab
14. abaaabaaaaab ⇒ aaaaaab
15. abaaabaaaaaab ⇒ aaaaaaab
16. abaaabaaaaaaab ⇒ aaaaaaaab
17. abaaabaaaaaaaab ⇒ aaaaaaaaab
18. abaaabaaaaaaaaab ⇒ aaaaaaaaaab
19. abaaabaaaaaaaaaab ⇒ aaaaaaaaaaab
20. abaaabaaaaaaaaaaab ⇒ aaaaaaaaaaaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa149lf:140,lp:9,rf:129,rp:11
[2/1]ab82lf:51,lp:11,ls:20,rf:29,rp:9,rs:20,lsrp:9,lprs:11,lsrs:20
[2/2]ba31lf:31,rf:9
[3/0]aaa111lf:102,lp:9,rf:109,rp:10
[3/1]aab56lf:38,ls:18,rf:20,rp:1,rs:20,re:1,lsrs:18
[3/2]aba42lf:31,lp:11,rf:9,rp:9
[3/3]baa29lf:29,rf:9
[3/4]bab4lf:2,ls:2
[4/0]aaaa75lf:66,lp:9,rf:90,rp:9,a:2
[4/1]aaab52lf:36,ls:16,rf:19,rp:1,rs:19,re:1,lsrs:16
[4/2]abaa40lf:29,lp:11,rf:9,rp:9
[4/3]baaa27lf:27,rf:9
[4/4]aaba20lf:20
[4/5]abab4lf:2,ls:2
[4/6]baab4lf:2,ls:2,a:1
[5/0]aaaab46lf:23,lp:9,ls:14,rf:18,rp:1,rs:18,re:1,lprs:9,lsrs:14,a:2
[5/1]aaaaa43lf:43,rf:72,rp:8,a:3
[5/2]abaaa38lf:27,lp:11,rf:9,rp:9
[5/3]aaaba20lf:20
[5/4]aabaa18lf:18,a:1
[5/5]baaab15lf:13,ls:2
[5/6]baaaa14lf:14,rf:9,a:3
[6/0]aaaaaa31lf:31,rf:56,rp:7,a:4
[6/1]abaaab26lf:13,lp:11,ls:2
[6/2]aaaaab24lf:12,ls:12,rf:16,rp:1,rs:16,re:1,lsrs:12,a:3
[6/3]aaaaba18lf:9,lp:9,a:5
[6/4]aaabaa18lf:18,a:1
[6/5]aabaaa16lf:16,a:2
[6/6]abaaaa14lf:14,rf:9,rp:9,a:3
[7/0]abaaaba22lf:11,lp:11
[7/1]aaaaaaa21lf:21,rf:42,rp:6,a:9
[7/2]aaaaaab20lf:10,ls:10,rf:14,rp:1,rs:14,re:1,lsrs:10,a:4
[7/3]aaaabaa16lf:8,lp:8,a:6
[7/4]aaabaaa16lf:16,a:2
[7/5]aabaaaa14lf:14,a:3
[7/6]abaaaaa12lf:12,rf:8,rp:8,a:4

Considering [length 7 / frequency 0] abaaaba=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaabab=aab⟩.