Morphocompletion for #476 ⟨a, b | ababba=ab⟩

Back:⟨a, b | ababba=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbaa ⇒ ab
2. ababb ⇒ abbba
3. abbbbaa ⇒ abb
4. abbbabaa ⇒ abab
5. abbabb ⇒ abbbba
6. abbbbbaa ⇒ abbb
7. abbbbabaa ⇒ abbab
8. abbbabb ⇒ abbbbba
9. abbbababaa ⇒ ababab
10. abbbbbbaa ⇒ abbbb
11. abbbbbabaa ⇒ abbbab
12. abbbbabb ⇒ abbbbbba
13. abbbbababaa ⇒ abbabab
14. abbbbbbbaa ⇒ abbbbb
15. abbbbbbabaa ⇒ abbbbab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] abb, [3/1] bbb, [3/2] baa, [3/3] bba, [3/4] bab, [3/5] aba
Length 4:[4/0] abbb, [4/1] bbbb, [4/2] bbba, [4/3] abaa, [4/4] bbaa, [4/5] bbab, [4/6] babb
Length 5:[5/0] abbbb, [5/1] babaa, [5/2] bbbaa, [5/3] bbbbb, [5/4] bbbba, [5/5] bbbab, [5/6] abbba
Length 6:[6/0] abbbbb, [6/1] abbbba, [6/2] bbbbaa, [6/3] bbabaa, [6/4] abbbab, [6/5] bbbaba, [6/6] bbbbab
Length 7:[7/0] bbbabaa, [7/1] abbbbbb, [7/2] abbbbab, [7/3] bbbbbaa, [7/4] abbbbba, [7/5] bbbbaba, [7/6] abbbaba

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababba=ab⟩.