Morphocompletion for #4754 ⟨a, b | abaaaaab=aab⟩

Solved by morph:6/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abaaaaab ⇒ aab
2. abaaaaaab ⇒ aaab
3. abaaaaaaab ⇒ aaaab
4. abaaaaaaaab ⇒ aaaaab
5. abaaaaaaaaab ⇒ aaaaaab
6. abaaaaaaaaaab ⇒ aaaaaaab
7. abaaaaaaaaaaab ⇒ aaaaaaaab
8. abaaaaaaaaaaaab ⇒ aaaaaaaaab
9. abaaaaaaaaaaaaab ⇒ aaaaaaaaaab
10. abaaaaaaaaaaaaaab ⇒ aaaaaaaaaaab
11. abaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaab
12. abaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaab
13. abaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaab
14. abaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaab
15. abaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaab
16. abaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaab
17. abaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaab
18. abaaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaab
19. abaaaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaab
20. abaaaaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa270lf:270,rf:210,rp:20
[2/1]ab80lf:40,lp:20,ls:20,rf:20,rs:20,lprs:20,lsrs:20
[2/2]ba20lf:20
[3/0]aaa250lf:250,rf:190,rp:19
[3/1]aab40lf:20,ls:20,rf:20,rp:1,rs:20,re:1,lsrp:1,lsrs:20
[3/2]aba40lf:20,lp:20
[3/3]baa20lf:20
[4/0]aaaa230lf:230,rf:171,rp:18
[4/1]aaab40lf:20,ls:20,rf:19,rp:1,rs:19,re:1,lsrp:1,lsrs:19
[4/2]abaa40lf:20,lp:20
[4/3]baaa20lf:20
[5/0]aaaaa210lf:210,rf:153,rp:17
[5/1]aaaab40lf:20,ls:20,rf:18,rp:1,rs:18,re:1,lsrp:1,lsrs:18
[5/2]abaaa40lf:20,lp:20
[5/3]baaaa20lf:20
[6/0]aaaaaa190lf:190,rf:136,rp:16,a:1
[6/1]aaaaab40lf:20,ls:20,rf:17,rp:1,rs:17,re:1,lsrp:1,lsrs:17
[6/2]abaaaa40lf:20,lp:20
[6/3]baaaaa20lf:20
[7/0]aaaaaaa171lf:171,rf:120,rp:15,a:2
[7/1]abaaaaa40lf:20,lp:20
[7/2]aaaaaab38lf:19,ls:19,rf:16,rp:1,rs:16,re:1,lsrp:1,lsrs:16,a:1
[7/3]baaaaaa19lf:19,a:1
[7/4]baaaaab2lf:1,ls:1

Considering [length 6 / frequency 1] aaaaab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaaaab=aab⟩.