Morphocompletion for #4749 ⟨a, b | aabbbbba=baa

Solved by morph:6/2,5/0,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbbbba ⇒ baa
2. aabbbbbbaa ⇒ babaa
3. aabbbbbbbaa ⇒ babbaa
4. aabbbbbbabaa ⇒ bababaa
5. aabbbbbbbbaa ⇒ babbbaa
6. aabbbbbbabbaa ⇒ bababbaa
7. aabbbbbbbabaa ⇒ babbabaa
...

Collecting factors up to length 7, frequency 3:

Length 2:[2/0] bb, [2/1] aa, [2/2] ba
Length 3:[3/0] bbb, [3/1] aab, [3/2] baa
Length 4:[4/0] bbbb, [4/1] aabb, [4/2] bbba
Length 5:[5/0] bbbbb, [5/1] aabbb, [5/2] bbbba
Length 6:[6/0] aabbbb, [6/1] bbbbbb, [6/2] bbbbba

Considering [length 6 / frequency 2] bbbbba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaccccc ⇒ ca
2. baa ⇒ aac
3. bca ⇒ cac
4. baca ⇒ aacaccccc
5. bcca ⇒ cacaccccc
6. bacca ⇒ aacacccccaccccc
7. bccca ⇒ cacacccccaccccc
8. baccca ⇒ aacacccccacccccaccccc
9. bcccca ⇒ cacacccccacccccaccccc
10. bacccca ⇒ aacacccccacccccacccccaccccc
11. bccccca ⇒ cacacccccacccccacccccaccccc
12. baccccca ⇒ aacacccccacccccacccccacccccaccccc
13. bcccccca ⇒ cacacccccacccccacccccacccccaccccc
14. bacccccca ⇒ aacacccccacccccacccccacccccacccccaccccc
15. bccccccca ⇒ cacacccccacccccacccccacccccacccccaccccc
16. baccccccca ⇒ aacacccccacccccacccccacccccacccccacccccaccccc
17. bcccccccca ⇒ cacacccccacccccacccccacccccacccccacccccaccccc
18. bacccccccca ⇒ aacacccccacccccacccccacccccacccccacccccacccccaccccc
19. bccccccccca ⇒ cacacccccacccccacccccacccccacccccacccccacccccaccccc
20. bbbbba ⇒ c
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] cc, [2/1] ca, [2/2] ba, [2/3] bc, [2/4] ac
Length 3:[3/0] ccc, [3/1] cca, [3/2] bcc, [3/3] bac, [3/4] acc
Length 4:[4/0] cccc, [4/1] ccca, [4/2] bccc, [4/3] bacc, [4/4] accc
Length 5:[5/0] ccccc, [5/1] cccca, [5/2] bcccc, [5/3] baccc, [5/4] acccc

Considering [length 5 / frequency 0] ccccc=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ca ⇒ aad
2. cda ⇒ daad
3. dc ⇒ cd
4. cdda ⇒ ddaad
5. cddda ⇒ dddaad
6. aadadadadad ⇒ da
7. cdddda ⇒ ddddaad
8. ccccc ⇒ d
9. cddddda ⇒ dddddaad
10. aadadadadacd ⇒ dac
11. cdddddda ⇒ ddddddaad
12. aadadadadaccd ⇒ dacc
13. cddddddda ⇒ dddddddaad
14. aadadadadacccd ⇒ daccc
15. cdddddddda ⇒ ddddddddaad
16. aadadadadaccccd ⇒ dacccc
17. baa ⇒ aac
18. bda ⇒ aadaaddadadad
19. bada ⇒ aaaaddadadadad
20. bbbbba ⇒ c
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] da, [2/1] dd, [2/2] cd, [2/3] ad, [2/4] cc
Length 3:[3/0] ada, [3/1] ddd, [3/2] dad, [3/3] cdd, [3/4] dda
Length 4:[4/0] adad, [4/1] dddd, [4/2] dada, [4/3] cddd, [4/4] ddda
Length 5:[5/0] adada, [5/1] dadad, [5/2] cdddd, [5/3] ddddd, [5/4] dddda

Considering [length 2 / frequency 0] da=e.

Step 4

Rewriting system is complete. See a, b | aabbbbba=baa.