Morphocompletion for #4691 ⟨a, b | aabbaaba=baa⟩

Back:⟨a, b | aabbaaba=baa⟩

Solved by morph:4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbaaba ⇒ baa
2. aabbbaa ⇒ babaaba
3. aabbaabbaa ⇒ babaa
4. aabbbabaa ⇒ babaabbaa
5. aabbbabbaa ⇒ babbabaaba
6. aabbaabbabaa ⇒ bababaa
7. babaababbaaba ⇒ aabbbbaa
8. aabbaabbbbaa ⇒ babbbaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aab, [3/1] baa, [3/2] bba, [3/3] abb, [3/4] aba, [3/5] bab, [3/6] bbb
Length 4:[4/0] aabb, [4/1] bbaa, [4/2] abba, [4/3] baab, [4/4] abaa, [4/5] aaba, [4/6] bbba
Length 5:[5/0] aabba, [5/1] abbaa, [5/2] aabbb, [5/3] babaa, [5/4] bbaab, [5/5] baaba, [5/6] bbbaa
Length 6:[6/0] aabbaa, [6/1] aabbba, [6/2] abbaab, [6/3] bbabaa, [6/4] bbaaba, [6/5] bbaabb, [6/6] babbaa
Length 7:[7/0] aabbaab, [7/1] aabbbab, [7/2] abbaaba, [7/3] abbaabb, [7/4] bbbabaa, [7/5] bbabbaa, [7/6] abbbbaa

Considering [length 4 / frequency 1] bbaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbaaba=baa⟩.