Morphocompletion for #4675 ⟨a, b | aababbba=baa

Solved by morph:6/1,3/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababbba ⇒ baa
2. aababbbbaa ⇒ babaa
3. aababbbbbaa ⇒ babbaa
4. aababbbbabaa ⇒ bababaa
5. aababbbbbbaa ⇒ babbbaa
6. aababbbbabbaa ⇒ bababbaa
7. aababbbbbabaa ⇒ babbabaa
...

Collecting factors up to length 7, frequency 3:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba
Length 3:[3/0] bbb, [3/1] aab, [3/2] baa
Length 4:[4/0] aaba, [4/1] bbbb, [4/2] bbba
Length 5:[5/0] aabab, [5/1] babbb, [5/2] ababb
Length 6:[6/0] aababb, [6/1] ababbb, [6/2] babbbb

Considering [length 6 / frequency 1] ababbb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aacaccca ⇒ caa
2. aacacccc ⇒ cac
3. baa ⇒ aca
4. bac ⇒ acc
5. bcaa ⇒ acacaccca
6. bcac ⇒ acacacccc
7. bccaa ⇒ acacacccacaccca
8. bccac ⇒ acacacccacacccc
9. bcccaa ⇒ acacacccacacccacaccca
10. bcccac ⇒ acacacccacacccacacccc
11. bccccaa ⇒ acacacccacacccacacccacaccca
12. bccccac ⇒ acacacccacacccacacccacacccc
13. bcccccaa ⇒ acacacccacacccacacccacacccacaccca
14. bcccccac ⇒ acacacccacacccacacccacacccacacccc
15. bccccccaa ⇒ acacacccacacccacacccacacccacacccacaccca
16. bccccccac ⇒ acacacccacacccacacccacacccacacccacacccc
17. bcccccccaa ⇒ acacacccacacccacacccacacccacacccacacccacaccca
18. bcccccccac ⇒ acacacccacacccacacccacacccacacccacacccacacccc
19. bccccccccaa ⇒ acacacccacacccacacccacacccacacccacacccacacccacaccca
20. ababbb ⇒ c
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] cc, [2/1] bc, [2/2] aa, [2/3] ac, [2/4] ca
Length 3:[3/0] ccc, [3/1] bcc, [3/2] cac, [3/3] caa, [3/4] cca
Length 4:[4/0] cccc, [4/1] bccc, [4/2] ccaa, [4/3] ccca, [4/4] ccac
Length 5:[5/0] bcccc, [5/1] ccccc, [5/2] cccaa, [5/3] cccac, [5/4] cccca

Considering [length 3 / frequency 0] ccc=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cd ⇒ dc
2. aacada ⇒ caa
3. aacadd ⇒ cad
4. aacadc ⇒ cac
5. ccc ⇒ d
6. baa ⇒ aca
7. bad ⇒ adc
8. bdaa ⇒ acacadacadacada
9. bdad ⇒ acacadacadacadd
10. bac ⇒ acc
11. bdac ⇒ acacadacadacadc
12. bcaa ⇒ acacada
13. bdcaa ⇒ acacadacadacadacada
14. bcad ⇒ acacadd
15. bdcad ⇒ acacadacadacadacadd
16. bcac ⇒ acacadc
17. bccaa ⇒ acacadacada
18. bccad ⇒ acacadacadd
19. bccac ⇒ acacadacadc
20. ababbb ⇒ c
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] aa, [2/1] ad, [2/2] bc, [2/3] ca, [2/4] ac
Length 3:[3/0] cad, [3/1] bcc, [3/2] bca, [3/3] bda, [3/4] caa
Length 4:[4/0] bcca, [4/1] aaca, [4/2] bdca, [4/3] acad, [4/4] abbb
Length 5:[5/0] aacad, [5/1] babbb, [5/2] ababb, [5/3] acadc, [5/4] acadd

Considering [length 3 / frequency 0] cad=e.

Step 4

Rewriting system is complete. See a, b | aababbba=baa.