Morphocompletion for #467 ⟨a, b | abaaab=ba⟩

Back:⟨a, b | abaaab=ba⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaab ⇒ ba
2. abaaba ⇒ baaaab
3. aababaa ⇒ baaaaab
4. aaabbaaa ⇒ baaaaaab
5. baaaaabab ⇒ aabba
6. baaaabaab ⇒ ababa
7. baaabaaaab ⇒ ababaa
8. ababaaaaab ⇒ baabaa
9. baaabaaaaab ⇒ aabbaaa
10. abbaaaaaab ⇒ babaaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] baa, [3/3] aba, [3/4] bab, [3/5] abb, [3/6] bba
Length 4:[4/0] aaab, [4/1] baaa, [4/2] aaaa, [4/3] abaa, [4/4] aaba, [4/5] abab, [4/6] abba
Length 5:[5/0] aaaab, [5/1] baaaa, [5/2] baaab, [5/3] abaaa, [5/4] aaaaa, [5/5] abaab, [5/6] aabab
Length 6:[6/0] aaaaab, [6/1] baaaaa, [6/2] abbaaa, [6/3] ababaa, [6/4] baaaba, [6/5] baaaab, [6/6] abaaaa
Length 7:[7/0] baaaaab, [7/1] baaabaa, [7/2] abbaaaa, [7/3] ababaaa, [7/4] aabbaaa, [7/5] aaabbaa, [7/6] baaaaba

Considering [length 4 / frequency 0] aaab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaab=ba⟩.