Morphocompletion for #4659 ⟨a, b | aababbaa=baa⟩

Back:⟨a, b | aababbaa=baa⟩

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababbaa ⇒ baa
2. aababbbaa ⇒ bbaa
3. aababbabaa ⇒ babaa
4. aababbbbaa ⇒ bbbaa
5. aababbabbaa ⇒ babbaa
6. aababbbabaa ⇒ bbabaa
7. aababbbbbaa ⇒ bbbbaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] baa, [3/1] aab, [3/2] bab, [3/3] aba, [3/4] bba, [3/5] abb, [3/6] bbb
Length 4:[4/0] aaba, [4/1] bbaa, [4/2] babb, [4/3] abab, [4/4] bbba, [4/5] abbb, [4/6] abba
Length 5:[5/0] aabab, [5/1] ababb, [5/2] bbbaa, [5/3] babbb, [5/4] babba, [5/5] babaa, [5/6] abbaa
Length 6:[6/0] aababb, [6/1] bbbbaa, [6/2] bbabaa, [6/3] babbaa, [6/4] ababbb, [6/5] ababba, [6/6] babbbb
Length 7:[7/0] aababbb, [7/1] aababba, [7/2] bbbbbaa, [7/3] bbbabaa, [7/4] bbabbaa, [7/5] babbbaa, [7/6] abbbbaa

Considering [length 6 / frequency 0] aababb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aababbaa=baa⟩.