Morphocompletion for #4647 ⟨a, b | aabababa=baa

Solved by morph:5/1,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabababa ⇒ baa
2. aabababbaa ⇒ babaa
3. aabababbbaa ⇒ babbaa
4. aabababbabaa ⇒ bababaa
5. aabababbbbaa ⇒ babbbaa
6. aabababbabbaa ⇒ bababbaa
7. aabababbbabaa ⇒ babbabaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] aab, [3/3] baa
Length 4:[4/0] abab, [4/1] aaba, [4/2] baba, [4/3] bbaa
Length 5:[5/0] aabab, [5/1] ababa, [5/2] babab, [5/3] ababb
Length 6:[6/0] aababa, [6/1] ababab, [6/2] bababb, [6/3] bbabaa

Considering [length 5 / frequency 1] ababa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baa ⇒ acba
2. abc ⇒ cba
3. bac ⇒ acbc
4. ababa ⇒ c
5. aacacbcba ⇒ ca
6. aacacbcacba ⇒ caa
7. aacacbcacacba ⇒ caaa
8. aacacbcbc ⇒ cc
9. aacacbcacbc ⇒ cac
10. aacacbcacacbc ⇒ caac
11. acbbca ⇒ bcacba
12. acbbcc ⇒ bcacbc
13. acacbcacbcba ⇒ bca
14. acacbcacbcacba ⇒ bcaa
15. acacbcacbcbc ⇒ bcc
16. acacbcacbcacbc ⇒ bcac
17. acbcbbca ⇒ bbcacba
18. acbbcbca ⇒ bcbcacba
19. acbcbbcc ⇒ bbcacbc
20. acbcacbcacbcba ⇒ bbca
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ac, [2/1] bc, [2/2] cb, [2/3] ca, [2/4] ba, [2/5] aa, [2/6] bb
Length 3:[3/0] acb, [3/1] cbc, [3/2] cac, [3/3] bca, [3/4] aca, [3/5] cba, [3/6] aac
Length 4:[4/0] acbc, [4/1] cacb, [4/2] acac, [4/3] cbca, [4/4] bcac, [4/5] aaca, [4/6] cbcb
Length 5:[5/0] cacbc, [5/1] acacb, [5/2] acbca, [5/3] cbcac, [5/4] aacac, [5/5] bcacb, [5/6] acbcb

Considering [length 3 / frequency 0] acb=d.

Step 3

Rewriting system is complete. See a, b | aabababa=baa.