Morphocompletion for #4647 ⟨a, b | aabababa=baa⟩

Solved by morph:5/1,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabababa ⇒ baa
2. aabababbaa ⇒ babaa
3. aabababbbaa ⇒ babbaa
4. aabababbabaa ⇒ bababaa
5. aabababbbbaa ⇒ babbbaa
6. aabababbabbaa ⇒ bababbaa
7. aabababbbabaa ⇒ babbabaa
...

Collecting factors up to length 7 / frequency 4:

[2/0]aa26lf:13,lp:7,ls:6,rf:7,rs:7,lprs:7,lsrs:6
[2/1]ba25lf:24,ls:1,rf:16,rp:7,lsrp:1
[2/2]ab24lf:24,rf:9
[2/3]bb11lf:11,rf:5,a:1
[3/0]aba18lf:17,ls:1,rf:5
[3/1]bab17lf:17,rf:9,rp:6
[3/2]aab14lf:7,lp:7
[3/3]baa12lf:6,ls:6,rf:7,rp:1,rs:7,re:1,lsrs:6
[4/0]abab14lf:14,rf:2
[4/1]aaba14lf:7,lp:7
[4/2]baba11lf:10,ls:1,rf:5,rp:3
[4/3]bbaa8lf:4,ls:4,rf:3,rs:3,lsrs:3,a:1
[5/0]aabab14lf:7,lp:7
[5/1]ababa9lf:8,ls:1,rf:1
[5/2]babab7lf:7,rf:2,rp:2
[5/3]ababb6lf:6,rf:1,a:1
[6/0]aababa14lf:7,lp:7
[6/1]ababab7lf:7
[6/2]bababb6lf:6,rf:1,rp:1,a:1
[6/3]bbabaa4lf:2,ls:2,rf:1,rs:1,lsrs:1,a:2

Considering [length 5 / frequency 1] ababa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baa ⇒ acba
2. abc ⇒ cba
3. bac ⇒ acbc
4. ababa ⇒ c
5. aacacbcba ⇒ ca
6. aacacbcacba ⇒ caa
7. aacacbcacacba ⇒ caaa
8. aacacbcbc ⇒ cc
9. aacacbcacbc ⇒ cac
10. aacacbcacacbc ⇒ caac
11. acbbca ⇒ bcacba
12. acbbcc ⇒ bcacbc
13. acacbcacbcba ⇒ bca
14. acacbcacbcacba ⇒ bcaa
15. acacbcacbcbc ⇒ bcc
16. acacbcacbcacbc ⇒ bcac
17. acbcbbca ⇒ bbcacba
18. acbbcbca ⇒ bcbcacba
19. acbcbbcc ⇒ bbcacbc
20. acbcacbcacbcba ⇒ bbca
...

Collecting factors up to length 6 / frequency 7:

[2/0]ac52lf:41,lp:10,ls:1,rf:10,rp:2,rs:3,lsrp:1,lprs:1,a:2
[2/1]bc37lf:31,ls:6,rf:14,rp:7,rs:3,lsrp:2,a:3
[2/2]cb36lf:36,rf:9,rp:1,a:2
[2/3]ca30lf:27,ls:3,rf:14,rp:5,rs:3,re:1,a:4
[2/4]ba19lf:10,lp:2,ls:7,rf:5,rs:5,lprs:1,a:1
[2/5]aa14lf:7,lp:6,ls:1,rf:5,rs:3,lprs:2,a:2
[2/6]bb5lf:5,rf:3,rp:3,a:15
[3/0]acb34lf:28,lp:6,rf:7,rp:2,a:2
[3/1]cbc30lf:25,ls:5,rf:4,rs:3,a:4
[3/2]cac24lf:24,rf:7,rp:1,rs:2,re:1,a:4
[3/3]bca18lf:15,ls:3,rf:9,rp:5,rs:2,re:1,lsrp:1,a:7
[3/4]aca16lf:12,lp:4,a:4
[3/5]cba12lf:6,ls:6,rf:5,rp:1,rs:5,re:1,a:2
[3/6]aac12lf:6,lp:6,rf:1,rs:1,lprs:1,a:4
[4/0]acbc28lf:22,lp:3,ls:3,rf:3,rp:1,rs:3,re:1,lprs:1,a:4
[4/1]cacb22lf:22,rf:5,a:4
[4/2]acac16lf:12,lp:4,a:4
[4/3]cbca14lf:13,ls:1,rf:1,a:7
[4/4]bcac12lf:12,rf:6,rp:3,rs:1,re:1,a:7
[4/5]aaca12lf:6,lp:6,a:4
[4/6]cbcb7lf:7,a:4
[5/0]cacbc22lf:19,ls:3,rf:2,rs:2,a:4
[5/1]acacb16lf:12,lp:4,a:4
[5/2]acbca13lf:12,lp:1,a:7
[5/3]cbcac12lf:12,rf:1,a:7
[5/4]aacac12lf:6,lp:6,a:4
[5/5]bcacb10lf:10,rf:5,rp:2,a:7
[5/6]acbcb9lf:7,lp:2,a:4

Considering [length 3 / frequency 0] acb=d.

Step 3

Rewriting system is complete. See ⟨a, b | aabababa=baa⟩.