Morphocompletion for #4644 ⟨a, b | aabababa=aab⟩

Back:⟨a, b | aabababa=aab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabab ⇒ aabba
2. aabbbaaa ⇒ aab
3. aabbab ⇒ aabbba
4. aabbaab ⇒ aabbbaa
5. aabbbbaaa ⇒ aabb
6. aabbbab ⇒ aabbbba
7. aabbbaab ⇒ aabbbbaa
8. aabbbbbaaa ⇒ aabbb
9. aabbbbab ⇒ aabbbbba
10. aabbbbaab ⇒ aabbbbbaa
11. aabbbbbbaaa ⇒ aabbbb
12. aabbbbbab ⇒ aabbbbbba
13. aabbbbbbbaaa ⇒ aabbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] bb, [2/2] ab, [2/3] ba
Length 3:[3/0] aab, [3/1] bbb, [3/2] abb, [3/3] bba, [3/4] bab, [3/5] aaa, [3/6] baa
Length 4:[4/0] aabb, [4/1] bbbb, [4/2] abbb, [4/3] bbba, [4/4] baaa, [4/5] bbab, [4/6] bbaa
Length 5:[5/0] aabbb, [5/1] bbaaa, [5/2] bbbbb, [5/3] abbbb, [5/4] bbbba, [5/5] bbbaa, [5/6] bbbab
Length 6:[6/0] aabbbb, [6/1] bbbaaa, [6/2] aabbba, [6/3] bbbbaa, [6/4] abbbbb, [6/5] bbbbab, [6/6] bbbbba
Length 7:[7/0] aabbbbb, [7/1] bbbbaaa, [7/2] aabbbba, [7/3] aabbbaa, [7/4] bbbbbaa, [7/5] abbbbbb, [7/6] bbbbbab

Considering [length 4 / frequency 0] aabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabababa=aab⟩.